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3 years ago

Can anyone help me out with this question? It doesn’t have to be a long answer, just a couple sentences. Thanks! ❤️

Mathematics

1 answer:

s2008m [1.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

I think both are the same because you have equations in the formula and what ever you do on one side you do to the other.

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If h(x) = 6 - x, what is the value of ( h o h)(10)?

fgiga [73]

(H o h)?
Although if x=10 then 6-10=-4.

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3 years ago

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Bob is building a wooden cabin. The cabin is 30 meters wide. He obtained a bunch of 17 meters long wooden beams for the roof of

qaws [65]

The roof will be in the shape of an isosceles triangle with a base length of 30 m and two sides that are 17 m. The two 17 m beams will have the same angle of elevation since they have to might in the middle.

So to find the angle of elevation, we can split the roof in half vertically to create a right triangle. The base will now be 15 m, and the hypotenuse will be 17. Now we can use a trigonometry function to solve for the angle. We know the hypotenuse and the side adjacent to the angle, so we can use cosine.

$cos(\theta) = \frac{adjacent}{hypotenuse}$

$cos(\theta)= \frac{15}{17}$

$cos^{-1}( \frac{15}{17})=\theta$

$\theta = 28.1^{\circ}$

The answer is 28.1 degrees

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3 years ago

Ruby signed up for a frequent-filer program. She receives 3400frequent-flier miles for the first round trip and 1200 miles for a

vovangra [49]

Answer: 8200 miles

Step-by-step explanation:

Based on the question, since she wants to go for five round trips, her first round trip is fixed at 3400 and she will have 4 more additional trips. This can them be calculated as:

= 3400 + 1200x

x = additional trips = 4

We then put the value of x into the equation

= 3400 + 1200x

= 3400 + 1200(4)

= 3400 + 4800

= 8200

She'll have 8200 mile after 5 round trips

3 0

3 years ago

What is the value of x and the length of segment DE?

Mandarinka [93]

Answer:

Part 1) $x=6.6\ units$

Part 2) $DE=16.2\ units$

Step-by-step explanation:

Part 1) Find the value of x

we know that

Triangles CDF and FDE are similar

therefore

The ratio of its corresponding sides is proportional and its corresponding angles are congruent

$CD/FD=FD/DE$

$\frac{5}{9}=\frac{9}{2x+3} \\ \\5*(2x+3)=9*9\\ \\10x+15=81\\ \\10x= 81-15\\ \\10x=66\\ \\ x=6.6\ units$

Part 2) Find the length of DE

$DE=2x+3$

substitute the value of x

$DE=2(6.6)+3=16.2\ units$

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3 years ago

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Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago