Answer:
sorry
where is the table
Step-by-step explanation:
plz send detailed question
You can make up your own lines on the paper or just get a new sheet of blank paper or graphing paper
9514 1404 393
Answer:
m = (5x -6)/(43y -4)
Step-by-step explanation:
Subtract 4m+6 to separate m-terms from other terms.
5x +4m -(4m +6) = 43my +6 -(4m +6)
5x -6 = 43my -4m
5x -6 = m(43y -4) . . . . factor out m
(5x -6)/(43y -4) = m . . . . divide by the coefficient of m
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
