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3 years ago

3. Nina has $20.14 in her purse. She buys lunch for $9.67. How much does she have left?

Mathematics

2 answers:

o-na [289]3 years ago

6 0

Answer:

Nina has $10.47 left.

Step-by-step explanation:

$20.14 minus $9.67 is $10.47

RoseWind [281]3 years ago

6 0

Answer:

$10.47

Step-by-step explanation:

Nina has $20.14.If she uses $9.67 for lunch then she would be left with($20.14-$9.67) which is equal to $10.47......

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I PROMISE BRAINLIST; 5-STARS; THANKS!! IT'S VERY SIMPLE; BELIEVE ME!!!!!

DochEvi [55]

Answer:

2. B

3. C

4. B

5. D

Step-by-step explanation:

2) The sequence is multiplying by -2 each time. This means that it is geometric.

The next two terms would be:

$32*-2=-64\\-64*-2=128\\128*-2=-256$

This means that the answer is B

3) The sequence is being multiplied by $\frac{1}{3}$ each time. This means that it is geometric.

The next 3 terms would be:

$3*\frac{1}{3} =1 \\\\1*\frac{1}{3} =\frac{1}{3} \\\\\frac{1}{3} *\frac{1}{3} =\frac{1}{9}$

I am assuming that the answer is C and that you were unable to type the fractions.

4) We know that the common difference is 1.5, so that is the coefficient of our variable and the starting value is 15. This means that we can write an equation as follows

$f(x)=1.5(x-1)+15$

Now we can find the first 4 terms

$f(1)=15.0\\f(2)=16.5\\f(3)=18.0\\f(4)=19.5$

This would mean that the answer is B

5) We know that this is a geometric series, we know the common ratio, and we know the first term. This means we can write the equation as follows

$f(x)=4.5(10)^{x-1}$

Now we can find the first 4 terms

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Unless you meant that the ratio was $\frac{1}{10}$ , the answer is D, none of the above

7 0

3 years ago

I really need help with this question

Step2247 [10]

Answer:

option (b) -3(3w-3.1)

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3 years ago

Read 2 more answers

Y = -2 x - 5 what is the answer help

blondinia [14]

Answer:

x = -5/2

Step-by-step explanation:

0 = -2x - 5

2x = -5

Divide^

x = -5/2

Hope this helped

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3 years ago

insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of

ss7ja [257]

Answer: $(13.22\%,\ 19.34\%)$

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : $\hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628$

$=16.28\%$

Significance level : $\alpha= 1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Confidence level for population proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)$

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= $(13.22\%,\ 19.34\%)$

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