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Kryger [21]
3 years ago
15

A hydrogen atom has a diameter of about 10nm

Physics
2 answers:
slega [8]3 years ago
5 0

1nm = 10^-9m

1micro = 10^-6m

1mm=10^-3m

10nm = 10x!0^-9m = 10^-8m

pentagon [3]3 years ago
4 0

1nm = 10^-9m

1micro = 10^-6m

1mm=10^-3m

10nm = 10x!0^-9m = 10^-8m

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A firearms company is testing a new model of rifle by firing a 7.50-g lead bullet into a block of wood having a mass of 17.5 kg.
Anestetic [448]

Answer:

Explanation:

Let the bullets speed be V .

Kinetic energy = 1/2 mV² where m is mass of bullet

This energy is converted into heat Q which raises the temperature of target by Δ T .

Q = mc Δ T  , m is mass , c is specific heat and Δ T is rise in temperature .

heat absobed by bullet

= .0075 x 130 x .040

= .039 J

heat absorbed by block of wood

= 17.5 x 1700 x .04

= 1190 J

Total heat absorbed

= 1190.039 J

So kinetic energy = heat absobed

= 1/2 x .0075 x V² = 1190.039

V² = 317343.73

V  = 563.33 m /s

8 0
3 years ago
Match each coordinate used on a globe of earth to its counterpart on the celestial sphere
nika2105 [10]
I hope it will help u!!!!!!!
Equator------------------C::::::::::::::
Latitude------------------B::::::::::::::
Longitude---------------A::::::::::::::
3 0
4 years ago
Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic colli
Pie

Answer:

a)  v = 3,843 m / s, b)  46.7º  North- East

Explanation:

Moment is a vector quantity, so one of the best ways to solve this problem is to solve each component separately.

The system is formed by the two vehicles so that the moment is preserved during the crash

Direction to the East    

initial instant. Before the crash

          p₀ = mₐ vₐ₀

final insttne. After the crash

          p_f = (mₐ + m_b) vₓ

         p₀ = p_f

         mₐ vₐ₀ = (mₐ + m_b) vₓ

         vₓ = \frac{m_a}{m_a + m_b} \ v_{ao}

let's calculate

          vₓ = \frac{16.7}{16.7 + 29.3} \ 7.26

          vₓ = 2,636 m / s

direction north

initial   p₀ = m_b v_{bo}

final     p_f = (mₐ + m_b) v_y

          p₀ = p_f

          m_b v_{bo} = (mₐ + m_b) v_y

          v_y = \frac{m_b}{m_a+m_b} \ v_{bo}

let's calculate

          v_y = \frac{29.3}{16.7 + 29.3} \ 4.39

          v_y = 2.796 m / s

the final speed of the two two vehicles is

          v = (2,636 i ^ + 2,796 j ^) m / s

a) the magnitude of the velocity

let's use the Pythagorean theorem

       v = \sqrt{v_x^2 + v_y^2}

      v = \sqrt{2.636^2 + 2.796^2}

      v = 3,843 m / s

b) let's use trigonometry to find the direction

      tan θ = v_y / vₓ

      θ = tan⁻¹ v_y / vₓ

      θ = tan⁻¹ (2,796 / 2,636)

      θ = 46.7º

This direction is 46.7º  North East

7 0
3 years ago
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
4 years ago
Read 2 more answers
4. A 100-kg soldier in the Arctic is coasting on his ice skates at a speed of 3.0 m/s. He fires 35 bullets directly forward from
FinnZ [79.3K]

Answer:

The gunner must apply 240 N  to the gun to stop it from moving back.

Explanation:

6 0
3 years ago
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