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liq [111]
4 years ago
9

A methane bubble starts at the bottom of a lake (15.0 meters down) where the water temperature is 4.00C and rises to the surface

where the water temperature is 22.0C (hey, it’s summer at Rock Lake, and this is a reasonable temperature.) and the air pressure is 0.920 atmospheres. Assuming the gas is ideal and rises slowly enough that its temperature changes exactly as the water does, find the factor by which the final volume is different than the initial.

Physics
1 answer:
elena-s [515]4 years ago
7 0

Answer:

the factor by which the final volume is different than the initial = 2.74

Explanation:

The detailed step and application of the general gas equation = PV/T =constant, is as shown in the attachment.

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The answer is C

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Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling w
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Solution :

c). $\vec{F}_A = $ force applied by Abe

   $\vec{F}_B = $ force applied by Barry

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$\vec{F}_A $  in the vector form can be written as :

         $\vec{F}_A = 0 \hat{i} + 60 \hat{j}$

$\vec{F}_B $  in the vector form can be written as :

         $\vec{F}_B = 60 \hat{i} + 0 \hat{j}$

The resultant,

$\vec{F}_R= \vec{F}_A+\vec{F}_B $

     $=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$

    $=60 \hat i + 60 \hat j$

$|\vec{F}_R| = \sqrt{60^2+60^2}$

        = 84.853 N

d). As the three forces are in equilibrium, therefore,

$|\vec F_E| = |\vec F_R|$

$|\vec F_E| =84.853 \ N$

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$

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Answer:

Explanation:

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Answer:

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