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emmasim [6.3K]
3 years ago
10

8x + 7 equals -9 solve for x

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
The answer to this equation is
x= (1/4)
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What is the solution to -4|-2x+6| = -24
AURORKA [14]
The answer is x1= 0, x2= 6
5 0
3 years ago
Is 8/9 greater than 5/10
Agata [3.3K]
Yes 8/9 is greater than 5/10
5 0
3 years ago
Read 2 more answers
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
Move two choices to the blanks to correctly complete the sentences.
Pavel [41]

Answer:

(A) There should have been 5 outcomes of HT

(B) The experimental probability is greater than the theoretical probability of HT.

Step-by-step explanation:

Given

S = \{HH,HT,TH,TT\} -- Sample Space

n(S) = 4 --- Sample Size

Solving (a); theoretical outcome of HT in 20 tosses

First, calculate the theoretical probability of HT

P(HT) = \frac{n(HT)}{n(S)}

P(HT) = \frac{1}{4}

Multiply this by the number of tosses

P(HT) * n= \frac{1}{4} * 20

P(HT) * n= 5

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Solving (b); experimental probability of HT

Here, we make use of the table

P(HT) = \frac{n(HT)}{n(S)}

P(HT) = \frac{6}{20}

P(HT) = 0.30 ---- Experimental Probability

In (a), the theoretical probability is:

P(HT) = \frac{1}{4}

P(HT) = 0.25 ---- Experimental Probability

By comparison;

0.30 > 0.25

6 0
3 years ago
A hot air balloon can hold up to 300 pounds of weight. The balloon's pilot weighs 140 pounds. How many 20-pound bags of sand (b)
Anit [1.1K]

Answer:

8 sand bags

Step-by-step explanation:

300 - 140 = 160

160 ÷ 20 = 8

8 sand bags of 20-pounds each.

7 0
2 years ago
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