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3 years ago

8x + 7 equals -9 solve for x

Mathematics

1 answer:

Montano1993 [528]3 years ago

8 0

The answer to this equation is
x= (1/4)

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COOKING Franklin is cooking a 3-pound turkey breast for 6 people. If the number of pounds of turkey varies directly with the num

Gwar [14]

Answer-

2, 4, and 8 people will need 1, 2, 4 pounds of turkey respectively.

Solution-

Given in the question, number of pounds of turkey varies directly with the number of people, i.e as the number of people increases or decreases, the pound of turkey also increases or decreases.

Taking,

x = number of people,

y = pounds of turkey.

This condition can be represented as,

$\Rightarrow y\ \alpha \ x\\\Rightarrow y=kx$

As given in the question, when x = 6 y = 3

$\Rightarrow 3=k\times 6$

$\Rightarrow k=\frac{3}{6}= \frac{1}{2}$

Now, putting the values of k in the equation, the equation becomes

$\Rightarrow y=\frac{1}{2}x$

Now, we can get the values of y or number of pounds of turkey needed by putting the given x or number of people.

All the calculations are shown in the attached table.

5 0

3 years ago

PLEASE HELP!! I REALLY NEED IT!!

Alchen [17]

the answer would be 6 planes

4 0

3 years ago

Read 2 more answers

Which set of numbers includes only integers?

Lelu [443]

Answer:

{14,23,654,0,9}

Step-by-step explanation:

The first three contain negative numbers and decimal points therefor the last one {14,23,654,0,9} is correct.

3 0

3 years ago

Read 2 more answers

(-2q^4)(-8q^3b^6) help I need to simplify this problem

Montano1993 [528]

Multiply the constants. Multiply the variables according to the rules of exponents.
$(-2q^{4})(-8q^{3}b^{6}) = ((-2)(-8))q^{(4+3)}b^{6}\\\\=16q^{7}b^6}$

4 0

3 years ago

If the expression (3^(d)*\sqrt(5))/(3^(2)*\sqrt(45)) is equal to 3, what is the value of d

Digiron [165]

$3^d\cdot\dfrac{\sqrt5}{3^2\cdot\sqrt{45}}=3\\\\\dfrac{3^d\sqrt5}{3^2\sqrt{9\cdot5}}=3\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\dfrac{3^d\sqrt5}{3^2\sqrt9\cdot\sqrt5}=3\\\\\dfrac{3^d}{3^2\cdot3}=3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{3^d}{3^{2+1}}=3\\\\\dfrac{3^d}{3^3}=3\qquad\text{multiply both sides by}\ 3^3\\\\3^d=3\cdot3^3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\3^d=3^{1+3}\\\\3^d=3^4\iff\boxed{d=4}$

8 0

3 years ago