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4 years ago

The variables y and x have a proportional relationship, and y = 15 when x = 3. What is the value of x when y = 4?

Mathematics

1 answer:

kenny6666 [7]4 years ago

5 0

Answer:

first equation:

y=kx

15=3(k)

k=5

second equation:

4=5x

x=4/5

Step-by-step explanation:

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Two race cars,car x an y,are at the starting point of a two km track at the same time.car x and car y make one lap every 60 s an

tino4ka555 [31]

Answer is attached.

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4 years ago

Can Someone Please Help!!!!

elena-14-01-66 [18.8K]

B) 16a+20

That’s the answer.

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3 years ago

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Use the following data set to find the standard deviation of the set. 46, 34, 25, 31, 15, 50, 37, 42

vekshin1

The given data exists 46, 34, 25, 31, 15, 50, 37, 42

Mean, μ = 35

Variance, σ² = 114.5

Standard deviation, σ = 10.7004

<h3>What is the standard deviation?</h3>

A standard deviation (or σ) exists as a measure of how dispersed the data exists concerning the mean. Low standard deviation indicates data exist clustered about the mean, and high standard deviation suggests data exist better spread out.

Given data 46, 34, 25, 31, 15, 50, 37, 42

The number of elements exists n = 8 (8 numbers in the set)

To calculate the mean,

(46+34+25+31+15+50+37+42)/8 = 280/8 = 35

μ = 35

To calculate the variance,

Sum of the squared difference between each number of the set and the mean divided by the number of elements of the sample minus one.

Variance = [(46-35)² + (34-35)² + (25-35)² + (31-35)² + (15-35)²+ (50-35)² + (37-35)² + (42-35)²]/8

= 916/8

= 114.5

σ² = 114.5

Standard deviation exists as the square root of the variance.

σ² = 114.5

√σ² = √114.5

σ = 10.7004

Therefore, the standard deviation exists at 10.70.

To learn more about standard deviation refer to:

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1 year ago

Find the sum of the equation

stealth61 [152]

Answer:

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

Step-by-step explanation:

1) Rewrite ${y}^{2}-2y+1y$ in the form ${a}^{2}-2ab+{b}^{2}$ , where a = y and b = 1.

$\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}$

2) Use Square of Difference: ${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$ .

$\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}$

3) Factor ${y}^{2}+6y-7$ .

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

$(y-1)(y-7)$

Outcome/Result: $\frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}$

4) Rewrite the expression with a common denominator.

$\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}$

5) Expand.

$\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}$

6) Collect like terms.

$\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}$

7) Simplify ${y}^{2}+(7y+6y)-6y$ to ${y}^{2}+13y-6y$

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

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2 years ago

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Suppose that 5% of the time Todd attends a concert twice a month, 40% of the time he attends a concert once a month, and 55% of

nikklg [1K]

Answer:

The expected value for the number of times Todd attends a concert during a month is 0.5.

Step-by-step explanation:

We have these following probabilities:

5% probability of attending a concert twice a month, which means that P(X = 2) = 0.05

40% probability of attending a concert once a month, which means that P(X = 1) = 0.4

55% probability of not attending a concert during the month, which means that P(X = 0) = 0.55

What is the expected value for the number of times Todd attends a concert during a month?

We multiply each value by its probability. So

$E(X) = 0.05*2 + 0.4*1 + 0.55*0 = 0.1 + 0.4 = 0.5$

The expected value for the number of times Todd attends a concert during a month is 0.5.

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3 years ago