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puteri [66]
2 years ago
6

Find the sum of the equation

Mathematics
2 answers:
stealth61 [152]2 years ago
5 0

Answer:

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

Step-by-step explanation:

1)  Rewrite {y}^{2}-2y+1y  in the form{a}^{2}-2ab+{b}^{2}, where a = y and b = 1.

\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}

2)  Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}.

\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}

3)  Factor {y}^{2}+6y-7.

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

(y-1)(y-7)

Outcome/Result: \frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}

4) Rewrite the expression with a common denominator.

\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}

5)  Expand.

\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}

6) Collect like terms.

\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}

7) Simplify  {y}^{2}+(7y+6y)-6y  to  {y}^{2}+13y-6y

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

Zina [86]2 years ago
4 0

\boldsymbol{\dfrac{y}{y^{2}-2y+1 }+\dfrac{6}{y^{2}+6y-7 } \ \ \to \ \ \ Exercise \ to \ solve.   }

Factor y² - 2y + 1. Factor y² + 6y -7.

\bf{\dfrac{y}{(y-1){2}  }+\dfrac{6}{(y-1)(y+7)}   }

To add or subtract expressions, expand them so their denominators are the same. The least common multiple of (y - 1)² and (y - 1)(y + 2) it is (x + y)(y - 1)². Multiply \bf{\frac{y}{(y-1)^{2} }  } by \bf{\frac{y+7}{y+7}. } Multiply \bf{\frac{6}{(y-1)(y+7)} \ by \ \frac{y-1}{y-1}. }

\bf{\dfrac{y(y+7)}{(y+7)(y-1)^{2}  }+\dfrac{6(y-1)}{(y+7)(y-1)^{2} }   }

Since \bf{\frac{y(y+7)}{(y+7)(y-1)^{2}  }\ and \ \frac{6(y-1)}{(y+7)(y-1)^{2} }   } have the same denominator, add their numerators to add them together.

\bf{\dfrac{y(y+7)+6(y-1)}{(y+7)(y-1)^{2}  }  }

Do the multiplications on y(y + 7) + 6(y - 1).

\bf{\dfrac{y^{2} +7+6y-1}{(y+7)(y-1)^{2}  }  }

Combine like terms in y² + 7y + 6y - 6.

\bf{\dfrac{13-6y+1}{(y+7)(y-1)^{2}  }  }

xpande (y+7)(y−1)².

\bf{\dfrac{13y-6+y^{2}  }{y^{3}+5y^{2}-13y+7  } \ \ \to \ \ \ Answer  }

\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

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Grace [21]

Answer:

K'= (-1,-1)

J'= (-1,-5)

L'= (0,-3)

Step-by-step explanation:

What you do here is, input the (x,y) coordinates into the translation.

For example, the original point K is (-3,5). Insert this into the translation.

(-3,5) → (-3+2, 5-8) = (-1,-3)

Repeat this for the next coordinates of L and J.

J= (-3,3)

(-3,3) → (-3+2, 3-8) = (-1,-5)

L= (-2, 5)

(-2, 5) → (-2+2, 5-8) = (0,-3)

5 0
3 years ago
If g(x)=2(x-4), find the value of x if g(x)=20
kherson [118]

Answer:

3) 14

Step-by-step explanation:

in the given equation replace the "g(x)" with the provided "20"

20=2(x-4) solve as usual

divide each side by 2

10=x-4

add 4 to each side

14=x

the value of x is 14

3 0
3 years ago
A bakery used 38 pounds of flour to make French bread and
fomenos

Answer:

since we are not given the options, I will write down a few equations that represent the number of French bread loaves and bagels:

  • a = number of loaves of French bread
  • b = number of bagels
  • available amount of flour = 38

2a + b ≤ 38

2a ≤ 38 - b

a ≤ (38 - b) / 2

a ≤ 19 - 0.5b

b ≤ 38 - 2a

b ≤ 2(19 - a)

Hopefully one of these equations is one of the choices given to you.

8 0
2 years ago
Help me please <br> !!!!!!!!!!!!
Tpy6a [65]

Answer:

40

Step-by-step explanation:

Angle Formed by Tangent and Secant = 1/2 (DIFFERENCE of Intercepted Arcs)

< WVT = 1/2 ( WT - UW)

3x+4    = 1/2 (( 14x +7) - (7x+11))

Distribute

3x+4    = 1/2 ( 14x +7 - 7x-11)

Combine like terms

3x+4    = 1/2 ( 7x -4 )

Multiply each side by 2

6x +8 = 7x-4

Subtract 6x from each side

+8 = x-4

Add 4 to each side

12 =x

WVT = 3x+4

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       = 36+4

       = 40

7 0
3 years ago
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