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ivolga24 [154]
3 years ago
7

A straight vertical wire carries a current of 1.0 A into the page in a region where the magnetic field strength is 0.60 T. What

is the magnitude and direction of the magnetic force on a 1.0 cm section of this wire if the magnetic field direction is toward the east
Physics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

force on the wire of section  cm will be 6\times 10^{-3}N

Direction of force on the wire will be in south direction        

Explanation:

We have given current in the wire i = 1 A

Magnetic field strength B = 0.6 T

We have to find the force on 1 cm section of the wire so l = 1 cm = 0.01 m

Force on the wire containing current is equal to

F=iBL

F=1\times 0.6\times 0.01=6\times 10^{-3}N

So force on the wire of section  cm will be 6\times 10^{-3}N

Direction of force on the wire will be in south direction

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Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
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a hockey puck with a mass of 0.11 kg is at rest on the horizontal frictionless surface of the rink. a player applies a horizonta
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The solution to this ques is available in the image.

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1 year ago
A 0.750 kg block is attached to a spring with spring constant 17.5 N/m. While the block is sitting at rest, a student hits it wi
Dmitriy789 [7]

Answer:

a

 A =  0.081 \  m

b

The value is  u =  0.2569 \  m/s

Explanation:

From the question we are told that

   The mass is  m  =  0.750 \ kg

   The spring constant is  k  =  17.5 \  N/m

    The instantaneous speed is  v  =  39.0 \  cm/s= 0.39 \  m/s

    The position consider is  x =  0.750A  meters from equilibrium point

   

Generally from the law of  energy conservation we have that

        The kinetic energy induced by the hammer  =  The energy stored in the spring

So

          \frac{1}{2} *  m * v^2  =  \frac{1}{2}  *  k  *  A^2

Here a is the amplitude of the subsequent oscillations

=>      A =  \sqrt{\frac{m *  v^ 2 }{ k} }

=>      A =  \sqrt{\frac{0.750 *  0.39 ^ 2 }{17.5} }

=>       A =  0.081 \  m

Generally from the law of  energy conservation we have that

The kinetic energy  by the hammer  =  The energy stored in the spring at the point considered   +   The kinetic energy at the considered point

             \frac{1}{2}  * m *  v^2 = \frac{1}{2}  * k x^2 + \frac{1}{2}  * m *  u^2

=>          \frac{1}{2}  * 0.750 *  0.39^2 = \frac{1}{2}  * 17.5* 0.750(0.081 )^2 + \frac{1}{2}  * 0.750 *  u^2

=>          u =  0.2569 \  m/s

3 0
2 years ago
Zookeepers carry a stretcher that holds a sleeping lion. The total mass of the stretcher and lion is 175 kg. The lion's forward
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Answer:

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What is the wavelength of a light of frequency 7.21?
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4 0
3 years ago
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