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3 years ago

7

A straight vertical wire carries a current of 1.0 A into the page in a region where the magnetic field strength is 0.60 T. What

is the magnitude and direction of the magnetic force on a 1.0 cm section of this wire if the magnetic field direction is toward the east

1 answer:

Advocard [28]3 years ago

5 0

Answer:

force on the wire of section cm will be $6\times 10^{-3}N$

Direction of force on the wire will be in south direction

Explanation:

We have given current in the wire i = 1 A

Magnetic field strength B = 0.6 T

We have to find the force on 1 cm section of the wire so l = 1 cm = 0.01 m

Force on the wire containing current is equal to

$F=iBL$

$F=1\times 0.6\times 0.01=6\times 10^{-3}N$

So force on the wire of section cm will be $6\times 10^{-3}N$

Direction of force on the wire will be in south direction

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Answer:

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$F_y=72.1698\,N$

Explanation:

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angle of kicking from the horizon, $\theta= 30^{\circ}$

velocity of the ball after being kicked, $v=18 m.s^{-1}$

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similarly

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$I=F\times t$ .........................(2)

where F is the force applied for t time.

Then from eq. (1) & (2)

$F\times t=m.v$

$F\times 5.3\times 10^{-2}= 7.65$

$F=144.3396\,N$

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$F_x=144.3396\times cos 30^{\circ}$

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&

$F_y=144.3396\times sin 30^{\circ}$

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Answer:

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t = Thickness of Slab = 0.2 m

Therefore,

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<u>Here, negative sign shows the loss of heat.</u>

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