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Aliun [14]
3 years ago
15

Percent Composition of KOH

Chemistry
1 answer:
Alika [10]3 years ago
7 0
Hydrogen H 1.797%
Oxygen O 28.517%
Potassium K 69.687%
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Answer:

the answer is calcium

Explanation:

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3 years ago
A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to
Drupady [299]

Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

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m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

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Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

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ludmilkaskok [199]
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