Answer:
1 :
Step 2 :
Equations which are never true :
2.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
2.2 Solve : 2x+1 = 0
Subtract 1 from both sides of the equation :
2x = -1
Divide both sides of the equation by 2:
x = -1/2 = -0.500
One solution was found :
x = -1/2 = -0.500
Answer:
D
Step-by-step explanation:
if a<b,then b<a is the answer
Answer:
The probability that none of the LED light bulbs are defective is 0.7374.
Step-by-step explanation:
The complete question is:
What is the probability that none of the LED light bulbs are defective?
Solution:
Let the random variable <em>X</em> represent the number of defective LED light bulbs.
The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.
A random sample of <em>n</em> = 10 LED light bulbs is selected.
The event of a specific LED light bulb being defective is independent of the other bulbs.
The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.
The probability mass function of <em>X</em> is:

Compute the probability that none of the LED light bulbs are defective as follows:


Thus, the probability that none of the LED light bulbs are defective is 0.7374.
Let T = cost of a taco
Let S = cost of a salad
(2 tacos + 1 salad) + (8 % of 2 tacos and 1 salad) + 3 = 13.80
2T + S + .08(2T + S) + 3 = 13.80
2T + 2.5 + .08(2T + 2.5) + 3 = 13.80
2T + 2.5 + .16T + .20 + 3 = 13.80
2.16T + 5.7 = 13.80
2.16T = 8.10
T = 8.10/2.16 = $3.75
Check: 2T + S + .08(2T + S) + 3 = 13.80
2(3.75) + 2.50 + .08(2(3.75)+2.5) + 3 = 13.80
7.5 + 2.5 + .08(10) + 3 = 13.8
13.80 = 13.80
Answer checks as correct
Answer:
![\displaystyle Dependency\:[Infinitely\:Many\:Solutions]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Dependency%5C%3A%5BInfinitely%5C%3AMany%5C%3ASolutions%5D)
Explanation:
In the bottom equation, moving
to the oppocite side will give you the linear standard equation above it, therefore numerous solutions will occur.
I am joyous to assist you at any time.