All categories

3 years ago

7700÷623 with answer and remainder

Mathematics

2 answers:

nevsk [136]3 years ago

7 0

12 with a remander 224

Free_Kalibri [48]3 years ago

3 0

$7700/623$
$= 623*12 + 224$

Therefore, the answer is 12 and the remainder is 224.

Hope this helps !

Photon

You might be interested in

Rationalize 2 / 2√2

horsena [70]

Answer:

$\frac{\sqrt{2} }{2}$

Step-by-step explanation:

$\frac{2}{2\sqrt{2} }$ * $\frac{2\sqrt{2} }{2\sqrt{2} }$ = $\frac{4\sqrt{2} }{8}$ = $\frac{\sqrt{2} }{2}$

6 0

4 years ago

What’s the answer for number 5

Paul [167]

Answer:

D. 343 3/4

Step-by-step explanation:

1 inch = 125 miles

There is a distance of 2 3/4 inches

The first thing you would do is double 125, since it is one inch, and 2 inches would another 125. Now you have 250. To get the rest, you would need to divide 125 by 4, getting 31.25. Now since the question needs 3/4 of 125, you multiply 31.25 by 3, which is 93.75. Now add 250, and 93.75. You get 343.75, or 343 3/4

8 0

3 years ago

If f(x)=-4x^2-6x-1 and g(x)=-x^2-5x+3 find (f – g)(x)

sukhopar [10]

$f(x)=-4x^2-6x-1\\\\g(x)=-x^2-5x+3\\\\(f-g)(x)=f(x)-g(x)=(-4x^2-6x-1)-(-x^2-5x+3)\\\\=-4x^2-6x-1+x^2+5x-3=(-4x^2+x^2)+(-6x+5x)+(-1-3)\\\\=-3x^2-x-4\to\boxed{B.}$

8 0

4 years ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

3 years ago

Test the null hypothesis Upper H 0 : (mu 1 minus mu 2 )equals 0H0: μ1−μ2=0 versus the alternative hypothesis Upper H Subscript a

Law Incorporation [45]

Answer:

The test statistic t is t=2.9037.

The null hypothesis is rejected.

For a significance level of 0.05, there is enough evidence to support the alternative hypothesis.

Step-by-step explanation:

The question is incomplete:

The sample 1, of size n1=25 has a mean of 1.15 and a standard deviation of 0.31.

The sample 2, of size n2=25 has a mean of 0.95 and a standard deviation of 0.15.

This is a hypothesis test for the difference between populations means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is α=0.05.

The difference between sample means is Md=0.2.

$M_d=M_1-M_2=1.15-0.95=0.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{0.31^2+0.15^2}{25}}\\\\\\s_{M_d}=\sqrt{\dfrac{0.119}{25}}=\sqrt{0.005}=0.069$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.2-0}{0.069}=\dfrac{0.2}{0.069}=2.9037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=25+25-2=48$

This test is a two-tailed test, with 48 degrees of freedom and t=2.9037, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>2.9037)=0.0056$

As the P-value (0.0056) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

8 0

4 years ago