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lesya692 [45]
3 years ago
13

Describe in detail what happens when the following are dissolved in water polar solute ch3oh vs nonpolar solute ch3(ch2)4ch3

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
7 0
The simple trick is "Like dissolves Like".

Water is a polar molecule. So it will dissolve polar compounds.

1. CH3OH is polar. So, it will dissolve. Non polar solute CH3(CH2)4CH3 will not.

2. CO2 is non polar. So it will not dissolve. 
And KF is an inorganic compound. So it will be soluble in water.
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 we need to get the total calories, we can get it by getting the average of calories of the protein, fat, and carbohydrates:
calories of protein = 15g x 4 KCal/g
                               = 60 KCal
calories of fat = 1 g x 9 KCal/g
                        = 9 kCal
calories of carbohydrates = 42 g x 4 KCal/g 
                                            = 168 Kcal
∴ the total calories = 60 + 9 + 168 = 237Kcal = 0.237 Cal
to get the resualt to two significant figures 
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3 years ago
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Based on the information, what is the balanced chemical equation representing the burning of butane?
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Answer:

OptionA. 2C4H10 + 13O2 —> 8CO2 + 10H20

Explanation:

Butane burns is air (O2) according to the equation:

C4H10 + O2 —> CO2 + H20

Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;

There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:

C4H10 + O2 —> 4CO2 + H20

Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:

C4H10 + O2 —> 4CO2 + 5H20

Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2

as shown below

C4H10 + 13/2O2 —> 4CO2 + 5H20

Now we multiply through by 2 clear off the fraction and we obtained:

2C4H10 + 13O2 —> 8CO2 + 10H20

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3 years ago
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Answer:

8×10^(-3) mol/L

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[H⁺] = 10^(-2.1)

[H⁺] = 0.00794...mol/L = 8×10^(-3) mol/L

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