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3 years ago

Describe in detail what happens when the following are dissolved in water polar solute ch3oh vs nonpolar solute ch3(ch2)4ch3

1 answer:

7 0

The simple trick is "Like dissolves Like".

Water is a polar molecule. So it will dissolve polar compounds.

1. CH3OH is polar. So, it will dissolve. Non polar solute CH3(CH2)4CH3 will not.

2. CO2 is non polar. So it will not dissolve.
And KF is an inorganic compound. So it will be soluble in water.

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BRAINIEST AND MAX POINTS

strojnjashka [21]

Answer:

precess a and b

Explanation:

8 0

3 years ago

Read 2 more answers

How many moles are in 19.6 g of Sodium (Na)? And the conversion factor?

Snezhnost [94]

Answer:

n=0.852 moles

Explanation:

Given mass is, m = 19.6 g

The molar mass of sodium is, M = 22.99 u

We need to find the no of moles in 19.6 of Sodium. We know that, no of moles is equal to given mass divided by molar mass.

$n=\dfrac{m}{M}\\\\n=\dfrac{19.6}{22.99}\\\\n=0.852$

So, there are 0.852 moles in 19.6 g of Sodium.

6 0

3 years ago

At a certain temperature, ethane has a vapor pressure of 304 torr and propane has a vapor pressure of 27 torr. What is the mole

SOVA2 [1]

Answer:

166 torr

Explanation:

Let’s call ethane Component 1 and propane Component 2.

According to Raoult’s Law,

$p_{1} = \chi_{1}p_{1}^{\circ}\\p_{2} = \chi_{2}p_{2}^{\circ}$

where

p₁ and p₂ are the vapour pressures of the components above the solution

χ₁ and χ₂ are the mole fractions of the components

p₁° and p₂° are the vapour pressures of the pure components.

Data:

p₁° = 304 torr

p₂° = 27 torr

n₁ = n₂

1. Calculate the mole fraction of each component

χ₁ = n₁/(n₁ + n₂)

χ₁ = n₁/n₁ + n₁)

χ₁ = n₁/(2n₁)

χ₁ = ½

χ₁ = 0.0.5

χ₂ = 1- χ₁ = 1- 0.5 = 0.5

2. Calculate the vapour pressure of the mixture

$p_{1} = 0.5 \times \text{304 torr} = \text{ 152 torr}\\p_{2} = 0.5 \times \text{27 torr} = \text{ 13.5 torr}\\p_{\text{tot}} = p_{1} + p_{2} = \text{152 torr + 13.5 torr} = \textbf{166 torr}$

$\text{The vapour pressure above the solution is $\boxed{\textbf{166 torr}}$}$

8 0

4 years ago

LOOK AT THE IMAGE FOR THE QUESTION PLEASE

Nostrana [21]

From the atomic clock that utilizes C-133 which has an approximate frequency of 9.193 x 109 Hz. The wavelength of the energy is calculated to be 0.0326m.

From the given information: