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devlian [24]
3 years ago
13

13 Apply Place a check mark in the box to indicate

Chemistry
2 answers:
Sergio039 [100]3 years ago
7 0

Answer:

A. ✔️Substitution

B. ✔️Insertion

C. ✔️Deletion

Explanation:

In A, the type of mutation that is shown is Substitution. In B, the type of mutation shown is Insertion and in C, the type of mutation shown is Deletion.

Mutation refers to the change in the DNA sequence. This occurs in an organism. In gene mutation, the structure of DNA molecule changes and produces a different allele of a gene. While in chromosome mutation, there is the change in the structure or number of the whole chromosomes in a particular cell.

Actually, mutations can take place both in prokaryotic cell and in eukaryotic cell.

In genetics, there are: Substitution, Insertion and Deletion mutations.

Substitution mutation is an exchange of one base for another. Insertion mutation is simply addition of one or more nucleotide pairs in a DNA sequence while Deletion mutation refers to the situation in which a sequence of DNA is left out when there is DNA replication.

Alekssandra [29.7K]3 years ago
7 0

Answer:

A. Substitution

B. Insertion

C. Deletion

Explanation:

A. There is a replacement in C G there is A T.

B. There is one more base.

C. There are 8 base there should be 9.

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mash [69]

We can store the copper sulphate solution in alumiun container, if cover on alumiun is present.

<h3>Can you store cuso4 in an aluminum container?</h3>

Aluminium is more reactive than copper so the Aluminium will displace copper sulphate from its solution by reacting with it but if there is cover on the aluminium then the alumium can't react with copper.

So we can store the copper sulphate solution in alumiun container.

Learn more about container here: brainly.com/question/11459708

3 0
2 years ago
Now that Snape and Dumbledore has taught you the finer points of hydration calculations they have a slightly more challenging pr
Mrrafil [7]

Answer:

The value of an integer x in the hydrate is 10.

Explanation:

Molarity=\frac{Moles}{Volume(L)}

Molarity of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

0.0366 M=\frac{n}{5.00 L}

n=0.0366 M\times 5 mol=0.183 mol

Mass of hydrated sodium carbonate = n= 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol+x18 g/mol

n=\frac{\text{mass of Compound}}{\text{molar mass of compound}}

0.183 mol=\frac{52.2 g}{106 g/mol+x\times 18 g/mol}

106 g/mol+x\times 18 g/mol=\frac{52.2 g}{0.183 mol}

Solving for x, we get:

x = 9.95 ≈ 10

The value of an integer x in the hydrate is 10.

6 0
3 years ago
How many nonbonding electron pairs are there in the lewis structure of the peroxide ion, o22−?
Tom [10]
There is 6 non - bonding pairs.
Let me show you one easy method to do this.
o22-, oxygen valence electron = 6 here we have two so total 12, and -2 that means we add electrons so it’s all equal to 14 right.
whenever need to find lone pair, subtract the number you get with the lowest multiple of 8.
here we total 14 valence electron right so lowest multiple of 8 would be 8.
so 14 - 8 = 6 and that is our answer.
Let me know if you have Problem with chemistry.
8 0
3 years ago
Read 2 more answers
What elements are being reduced and oxidized in this chemical formula?
dangina [55]

Answer: The element Na (Sodium) is getting oxidized and Hydrogen is getting reduced.

Explanation:

Oxidation reactions are the reactions in which addition of oxygen takes place.

Reduction reactions are the reactions in which loss of oxygen takes place.

For a given reaction:

2Na(s)+2H_2O(l)\rightarrow H_2(g)+2NaOH(aq.)

Sodium is getting oxidized because there is an addition of reaction with that element.

Hydrogen is getting reduced because there is a removal of oxygen with that element.

3 0
3 years ago
How did Thomson discover the electron?
Hoochie [10]

J. J. Thomson discovered electron by performing an experiment using cathode ray tubes. High voltage across is applied across two electrodes at that  causes a beam of particles to flow from the the negatively-charged electrode that is  cathode to  the positively-charged electrode that is anode. Properties of the particles, are tested using two oppositely-charged electric plates around the cathode ray. The cathode ray was deflected away from the negatively-charged electric plate and towards the positively-charged plate. This indicated that the cathode ray was composed of negatively-charged particles. And these negatively charged particles are called electrons.


4 0
4 years ago
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