How many grams of Kr are in 2.00 mol of Kr? (4)
2 answers:
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Answer:
See explanation.
Explanation:
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In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:
Thus, we proceed as follows:
Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:
Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:
Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:
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Answer:
1. the absolute pressure in the tank before filling = 217 kPa
2. the absolute pressure in the tank after filling = 312 kPa
3. the ratio of the mass after filling M2 to that before filling M1 = 1.44
The correct relation is option c ()
Explanation:
To find -
1. What is the absolute pressure in the tank before filling?
2. What is the absolute pressure in the tank after filling?
3. What is the ratio of the mass after filling M2 to that before filling M1 for this situation?
As we know that ,
Absolute pressure = Atmospheric pressure + Gage pressure
So,
Before filling the tank :
Given - Atmospheric pressure = 100 kPa , Gage pressure = 117 kPa
⇒Absolute pressure ( p1 ) = 100 + 117 = 217 kPa
Now,
After filling the tank :
Given - Atmospheric pressure = 100 kPa , Gage pressure = 212 kPa
⇒Absolute pressure (p2) = 100 + 212= 312 kPa
Now,
As given, volume is the same before and after filling,
i.e. =
As we know that, P ∝ M
⇒
⇒
⇒ ≈ 1.44
Now, as we know that PV = nRT
As V is constant
⇒ P ∝ MT
⇒ ∝ M
⇒
So, The correct relation is c option.