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Dimas [21]
3 years ago
9

How many grams of Kr are in 2.00 mol of Kr? (4)

Chemistry
2 answers:
Lina20 [59]3 years ago
8 0

Answer:

1 mole is equal to 1 moles Krypton, or 83.798 grams.

Explanation:

andrew11 [14]3 years ago
3 0
ANSWER: 168 grams of Kr
This is the rounded answer, but the full answer is 168.7 grams (I’m not sure if you need to use significant figures or not).
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Alan has been driving 20 mph for the last half hour. The truck next to him has been there for a while now, so Alan is
DochEvi [55]
I don’t quite understand
5 0
3 years ago
A 0.100 M oxalic acid, HO2CCO2H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution i
____ [38]

Answer:

pH = 4.09

Explanation:

molarity of oxalic acid in the solution

         = 0.1 x 25 / (25 + 35)

         = 0.0417 M

molarity of NaOH in the solution

          = 0.1 x 35 / (25 +35)

         = 0.0583 M

H2C2O4 + NaOH -------------------> NaHC2O4 + H2O

0.0417          0.0583                            0                0

0                      0.0166                         0.0417

now second acid -base titration  

NaHC2O4 + NaOH -------------------> Na2C2O4 + H2O

0.0417             0.0166                              0                0

0.0251                 0                                  0.0166         ---

now

pH = pKa2 + log [Na2C2O4 / NaHC2O4]

pH = 4.27 + log (0.0166 / 0.0251)

pH = 4.09

3 0
3 years ago
When you dissolve an antacid tablet in water and it produces bubbles, what kind of change is this?
prisoha [69]

Answer: B. a chemical change

Explanation:

3 0
3 years ago
How many particles are in 3.2 mole of neon gas
Cerrena [4.2K]

There are 1.93 x 10²⁴ particles

<h3>Further explanation</h3>

Given

3.2 moles of Neon gas

Required

Number of particles

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

<em>1 mol = 6.02.10²³ particles </em>

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So the number of particles for 3.2 moles :

N = 3.2 x 6.02.10²³

N = 1.93 x 10²⁴

or

we can describe it using Avogadro's number conversion factor

\tt 3.2~moles\times \dfrac{6.02\times 10^{23}}{1~mole}=1.93\times 10^{24}

7 0
3 years ago
A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c
andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

V= 9.583 L

n=?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=31.8 +273= 304.8 K

Putting value in the given equation:

\frac{PV}{RT}=n

n= \frac{4.972 \;atm\; X \;9.583 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 304.8}

Moles = 1.905 moles

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0
2 years ago
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