1.50 mol C3H8 X (3 mol CO2 / 1 mol C3H8) X (44.0 g CO2 / 1 mol CO2) = 198 g CO2
Answer: - 436.5 kJ.
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.
The given chemical reaction is,

Now we have to determine the value of
for the following reaction i.e,

According to the Hess’s law, if we divide the reaction by half then the
will also get halved and on reversing the reaction , the sign of enthlapy changes.
So, the value
for the reaction will be:


Hence, the value of
for the reaction is -436.5 kJ.
Answer: 84.56L
Explanation:
Initial volume of gas V1 = 100L
Initial temperature T1 = 135°C
Convert temperature in Celsius to Kelvin
( 135°C + 273 = 408K)
Final temperature T2 = 72°C
( 72°C + 273= 345K)
Final volume V2 = ?
According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.
Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2
100L/408K = V2/345K
To get the value of V2, cross multiply
100L x 345K = V2 x 408K
34500 = V2 x 408K
V2.= 34500/408
V2 = 84.56L
Thus, the volume of the gas becomes 84.56 liters
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