Answer:
3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄
The coefficients are 3, 1, 3, 1
Explanation:
From the question given above, the following data were:
Silver chloride reacts with sodium phosphate to yield sodium chloride and silver phosphate. This can be written as follow:
AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄
The above equation can be balanced as follow:
AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄
There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 3 in front of NaCl as shown below:
AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄
There are 3 atoms of Cl on the right side and 1 atom on the left. It can be balance by putting 3 in front of AgCl as shown below:
3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄
Thus, the equation is balanced.
The coefficients are 3, 1, 3, 1
I believe that it is B chemicals containing carbon
I believe this force would be called pressure!
Both active and passive transport move molecules
Answer:
CH3COONa : CH3COOH = 1.74 : 1 (required to prepare a buffer at PH = 5)
Explanation:
Given that :
PH = 5
Calculate proportions of ethanoic acid and Sodium ethanoate to prepare Buffer solution
solution :
PH = Pka + Log ( CH3COONa / CH3COOH )
5.0 = 4.76 + Log ( CH3COONa / CH3COOH )
∴ Log ( CH3COONa / CH3COOH ) = 0.24
( CH3COONa / CH3COOH ) = 1.74
Therefore : CH3COONa : CH3COOH
1.74 : 1
