Question

A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 mT magnetic field is perpendicular to both the rod and its velocity. What is the potential difference between the ends of the rod? 30 mV 15 mV 0 mV 12 mV 60 mV

Answer 1

Answer:

The potential difference is 60mV

Explanation:

 This problem bothers on  application of the expression for motion emf which is expressed as

$E= Blv$

where B= magnetic field in Tesla

           l= length of the conductor

           v= speed of conductor

Given data

l= 2 meters

v= 6 m/s

B= 5 Tesla

Applying the formula we have

$E=5*2*6= 60mV$