What planet has a red surface
2 answers:
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To solve the problem we must know about the relationship between Speed, distance, and Time.
<h3>What is the relationship between Speed, distance, and Time?</h3>We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,
The speed of the light is 30,060.12 km/sec.
Given to us
- The distance between the earth and the sun is 15000000km
- Light takes 499 seconds to reach earth from the sun.
We know that speed can be described as,
Therefore,
<h3>What is the speed of the light?</h3>Substitute the value,
Hence, the speed of the light is 30,060.12 km/sec.
Learn more about Speed, distance, and Time:
Answer:
Explanation:
When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:
Where is the length of the string and
the velocity of propagation. Use this expression to find the value of
.
The velocity of propagation is given by the expression:
Where is the desirable variable of the problem, the linear mass density, and
is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:
With the value of the tension and the velocity you can find the mass density:
Complete Question:
Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:
A. 2F
B. F/4
C. F/2
D. F
E. 4F
Answer:
D.
Explanation:
If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):
As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.
As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.