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Serhud [2]
3 years ago
15

What from the following list of statements about vectors is definitely true? (section 3.3) The magnitude of a vector can be smal

ler than length of one of its components. Magnitude of a vector is positive if it is directed in +x and negative if is is directed in -X direction. Magnitude of a vector can be zero if only one of components is zero. If vector A has bigger component along x direction than vector B, it immediately means, the vector A has bigger magnitude than vector B. Magnitude of a vector can be zero only if all components of a vector are zero.
Physics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

"Magnitude of a vector can be zero only if all components of a vector are zero."

Explanation:

"The magnitude of a vector can be smaller than length of one of its components."

Wrong, the magnitude of a vector is at least equal to the length of a component. This is because of the Pythagoras theorem. It can never be smaller.

"Magnitude of a vector is positive if it is directed in +x and negative if is is directed in -X direction."

False. Magnitude of a vector is always positive.

"Magnitude of a vector can be zero if only one of components is zero."

Wrong. For the magnitude of a vector to be zero, all components must be zero.

"If vector A has bigger component along x direction than vector B, it immediately means, the vector A has bigger magnitude than vector B."

Wrong. The magnitude of a vector depends on all components, not only the X component.

"Magnitude of a vector can be zero only if all components of a vector are zero."

True.

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A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 45 N. How f
kiruha [24]
Work is obtained by multiplying the force and the object's displacement. The force and displacement and force should be in the same direction in order to have work. 
                                      W = F x d
                                     d = W / F
Substituting the known values,
                                     d = 352 J / 45 N = 7.82 m
Thus, the displacement of the student is 7.82 m. 
8 0
4 years ago
Pressure and volume changes at a constant temperature can be calculated using
V125BC [204]

Answer:

Option A, Boyle's law

Explanation:

The complete question is

Pressure and volume changes at a constant temperature can be calculated using

a. Boyle's law. c. Kelvin's law.

b. Charles's law. d. Dalton's law.

Solution

In Boyle’s law, the gas is assumed to be ideal gas and at constant  temperature. With these two conditions fixed, Boyle’s established that volume of gas varies inversely with the absolute pressure.  

The basic mathematical representation of this phenomenon is as follows -  

P \alpha \frac{1}{V}

OR

P = \frac{k}{V} \\PV = k

Where P is the pressure of ideal gas, V is the volume and k is the constant of proportionality.

Hence, option A is correct

3 0
3 years ago
After t hours a freight train is s(t) = 18t2 − 2t3 miles due north of its starting point (for 0 ≤ t ≤ 9). (a) Find its velocity
BartSMP [9]

Answer:

Explanation:

Given the equation modelled by the height of the train given as:

s(t) = 18t²-2t³ for for 0 ≤ t ≤ 9

a) Velocity is the rate of change of displacement.

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Velocity at t = 3hrs is determiner by substituting t = 3 into the velocity function.

V = 36(3) -6(3)²

V= 108 - 72

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b) for Velocity at time = 7hrs

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V(7) = 252 - 294

V(7) = -42mi/hr

The velocity at t = 7hrs is -42mi/hr

c) Acceleration is the rate of change of velocity.

a(t) = dV(t)/dt

Given v(t) = 36t - 6t²

a(t) = 36 - 12t

Acceleration at t=1 is given as:

a(1) = 36 -12(1)

a(1) = 24mi/hr²

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