Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:
.
Amount of interest earned from higher-yielding account:
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be
.
Therefore, the man invested $60,000 at 6%.
I am not 100% sure but I think the answer is C I hope I helped you and Good luck
Answer:
8 cm
Step-by-step explanation:
You neglected to include any equations
Here is one way to solve:
length of each piece
352/22 = 16
Half a piece
16/2 = 8
Choice C
352/22/2 = l
I think you either need to double 35 or use a protractor. Hope this is helpful!
Answer:
-267
Step-by-step explanation:
this is because 11 ×2=22,22+3=25,25×-9= -225 and then the other bracket when I solved I had 42 and so -225-42 = -267