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2 years ago

Determine the sum -46.38 (-24.6)

1 answer:

8 0

Well, this equation as a sum would be -46.38 + -24.6
so the answer would be -70.98.

I hope this helps, and have a fantastic day!

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What is the value of x 21, 18, 10 or 29?

Hitman42 [59]

18. Set the the two equations equal and solve.

8 0

3 years ago

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Bella spent 15% of her paycheck at the mall, and 40% of that was spent at the

Bingel [31]

Answer:

$229

Step-by-step explanation:

Pay check = P

Total spent movie T = $13.74

T = 0.4 *0.15* P = $13.74

The 40% on the Movie Theatre spending is part of the 15% spending at the mall.

So 40% of 15% of the Pay Check = $13.74

P = $13.74 / (0.4*0.15) = 34.35/0.15 = 229

5 0

2 years ago

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Please help me with #12 pleaseee

lawyer [7]

The equation of a line can be expressed in slope intercept form as y = mx + b where m is the slope and b is the y-intercept. Horizontal lines have a slope of 0, so the equation is simply y=b.

The y value of the point given is -5, so the answer is y = -5.

8 0

2 years ago

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0

2 years ago

Two and one ninth minus seven sixth equals

tatiyna

.944
2 1/9 = 2.111
7/6 = 1.167
2.111-1.167= .944

4 0

2 years ago

Read 2 more answers