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Rom4ik [11]
3 years ago
5

Speaker City designs and manufactures high-end home theater speakers. Speaker City uses a standard overhead rate of 2.0 hours pe

r unit at a cost of $8.00 per hour. Data for the month of June shows that Speaker City produced 400 units and recorded actual overhead costs of $24,500. What is the total variable overhead variance for the month of June?
Business
1 answer:
olya-2409 [2.1K]3 years ago
8 0

Answer:

$18,100 unfavorable

Explanation:

The computation of the total variable overhead variance is shown below:

Total variable overhead variance = Standard variable overhead cost - Actual variable overhead cost

where,

Standard variable overhead cost is

= 2 hours × 400 units × $8 per hour

= $6,400

And, the actual variable overhead cost is $24,500

So, the  total variable overhead variance is

= $6,400 - $24,500

= $18,100 unfavorable

Since the actual variable overhead cost exceeds then the standard variable overhead cost so it reflects the unfavorable variance

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Manual Company sells goods to Nolan Company during 2017. It offers Nolan the following rebates based on total sales to Nolan. If
diamong [38]

Answer: See explanation

Explanation:

Based on the information given in the question, we should note that while using the gross method, the revenue gotten from sales will be calculated by subtracting the rebate of 2% from the full invoice amount of $110,000. This will be:

= $110,000 - (2% × $110,000)

= $110,000 - (0.02 × $110,000)

= $110,000 - $2200

= $107800

Using the net method, the revenue gotten from sales will be calculated by subtracting the rebate of 6% from the full invoice amount of $110,000. This will be:

= $110,000 - (6% × $110,000)

= $110,000 - (0.06 × $110,000)

= $110,000 - $6600

= $103400

5 0
3 years ago
You need a 30-year, fixed-rate mortgage to buy a new home for $210,000. Your mortgage bank will lend you the money at a 7.1 perc
miskamm [114]

Answer:

$573,963

Explanation:

First, calculate the present value of the loan payments using the following formula

PVA = PMT x [ ( 1 + r )^n - 1 ] / [ r ( 1 + r )^n)

PVA = $950 x [ ( 1 + 7.1%/12 )^360 - 1] / [ 7.1%/12 ( 1 + 7.1%/12 )^360)

PVA =  $141,362.32  

Now calculate the difference of Value of loan and the present value of loan payment

Difference = Loan value - PV of loan payment = $210,000 - $141,362.32 = $68,637.68

This te Ballon payment in present value term, We need to determine the value at the end of the loan term.

Hence we need to calculate the future value of this payment as follow

Future value = Present vale x ( 1 + Monthly Interest rate )^numbers of months

Future value = $68,637.68 x ( 1 + 7.1%/12 )^360

Future value = $573,963.09

Future value = $573,963

Hence the ballon Payment will be $573,963

7 0
3 years ago
KTZ manufactures and distributes cutting edge hockey equipment. It has decided to streamline some of its operations so that it w
Nady [450]

Answer:

Consider the following explanations and calculations

Explanation:

part 1

a)  KTZ sold an office building for $85,000 in cash. It originally bought the office building seven

years ago for $59,000 and has taken $14,000 in depreciation.-

Ans- Bookvalue on date of sale= $59000- $ 14000= $ 45000

Profit on sale of office building= $85000- $45000= $40000

As per section 1231, out of profit of $40,000, amount of $14000, i.e till the amount of depreciation will be an ordinary income and $26000 (40000-14000) will be considered capital income.

b)

KTZ sold another machine for $6,200. It originally purchased this machine six months ago for

$9,000 and has claimed $1,230 in depreciation expense against the asset.

Ans- As the asset was held for less than one year, the provision of section 1230 will not apply. Thus, the loss will be treated as ordinary loss. The amount of ordinary loss =cost-depreciation-salesprice=9000-1230-6200= $1570

c)

KTZ sold some of its inventory for $5,000 cash. This inventory had a basis of $8,000

Ans-Section 1230 will not be applied to inventories. Thus ordinary profit of $3000 (8000-3000) will be considered.

d)

KTZ held stock in XYZ Corp., which had a value of $19,000 at the beginning of the year. That

same stock had a value of $25,230 at the end of the year.

Ans- Stock is treated as lower of market value or cost, hence no treatment, willl be shown at $19000

e)

KTZ sold a machine that it used to make computerized dies for $26,300 cash. It originally bought

the machine for $16,200 three years ago and has taken $4,000 depreciation

Ans- Bookvalue of computer- 16200-4000= $12,200

Profit= 26300- 12200= $14100

As per section 1231, out of profit of $14,100, amount of $4000, i.e till the amount of depreciation will be an ordinary income and $10100 (14100-4000) will be considered capital income.

part 2

Net section 1231 gain=26,000 + 10100= $ $36100

Ordinary gain= 14000+3000+4000= $21000

Ordinary loss= $ 1570

5 0
3 years ago
Once a business has sold a service, it no longer needs to be concerned with customer satisfaction. True False
kobusy [5.1K]

Answer:

False

Explanation:

' Once a business has sold a service, it no longer needs to be concerned with customer satisfaction' is a False statement.

Customers are the pillars on which every business stands & their satisfaction should be a supreme priority for a business.

There is need of 'After Sale Services' after selling a service. This is important to ensure customer's expectations from the product are met, & they are satisfied with the business' services.

After sale services make customers feel valued. This generates customer retention, customers' loyalty towards business. Such customers are also likely to do word marketing & build a business' reputation in front of other customers.

4 0
3 years ago
Suppose 20.0 g pieces of gold and iron, both initially at 100oC, are added to different containers of water, both initially at 2
Sauron [17]

Answer:

  • The final temperature in the container with Gold is 27.49 ⁰C
  • The final temperature in the container with Iron is  33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

Explanation:

Q = mcΔT

Where;

Q is the quantity of heat gained or lost

m is the mass of the metals or water

c is the specific heat capacity

ΔT is the change in temperature, T₂ - T₁

T₂  is the final temperature and T₁ is the initial temperature

Heat lost by metals at 100°C is equal to heat gained by water at 25°C

-Q_{metal} = Q_{water}

-Q_{Au} = Q_{H_2O} \\-Q_{Fe}  = Q_{H_2O}

Specific heat capacity of water = 4.18 J/g°C

Specific heat capacity of gold = 0.129 J/g°C

Specific heat capacity of iron  = 0.45 J/g°C

⇒For Gold

-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)

-2.58T₂ +258 = 75.24T₂  - 1881

77.82T₂  = 2139

T₂  = 2139/77.82

T₂ = 27.49 ⁰C

⇒For Iron

-20*0.450*(T₂ - 100) = 18*4.18 (T₂  - 25)

-9T₂  +900 = 75.24T₂ - 1881

84.24T₂ = 2781

T₂  = 2781/84.24

T₂ = 33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

5 0
3 years ago
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