Question

What are the X- and y- intercepts of the line? 2x + 3y = -12

Answer 1

Y intercept = -4
x intercept = -6



if we are asked to find y intercept of a line
we should put 0 as x and solve for y :
$0 + 3y = - 12 \\ 3y = - 12 \\ y = \frac { - 12}{3} = - 4$
so y intercept is -4





if we are asked to find x intercept of a line, we should put 0 as y and solve for x :
$2x + 0 = - 12 \\ 2x = - 12 \\ x = \frac{ - 12}{2} = - 6$
x intercept is -6





good luck

Answer 2

Subtract 2x from both sides. 

3y = - 2x - 12

Divide every term by 3 to get the y-variable by itself.

y = - 2/3x - 4

Since the equation is not in slope-intercept form (y = mx + b), your y-intercept is just the number in the b slot. Y-intercept is - 4 or (0, - 4).

Now to find your x-intercept, plug in 0 where the y-variable is and solve for x.

0 = - 2/3x - 4
4 = - 2/3x 

Multiply both sides by - 3/2 to isolate the variable. 

4(- 3/2) = x
- 12/2 = x
- 6 = x.

Your x-intercept is - 6 or (- 6, 0).