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earnstyle [38]
3 years ago
9

A pony in a pony ride takes 42 seconds to make one circuit around a circle. The circumference of a circle is 84 m. What is the a

verage speed of the pony in meters per second?
Mathematics
2 answers:
o-na [289]3 years ago
8 0

Step-by-step explanation:

Average speed=<u>Total distance</u>

Total time

=<u> </u><u>8</u><u>4</u><u>m</u>

<u> </u> 42s.

=2m/s

kirza4 [7]3 years ago
5 0

Answer:

Average speed = 2 m/s

Step-by-step explanation:

speed = distance / time

speed = 84 m / 42 sec

speed = 2 m/s

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For the graph 2x - 3y - 7 = 0 <br> determine the coordinates of the axes intercepts.
Sliva [168]

Answer:

X intercept: (7/2, 0)

Y intercept: (0, -7/3)

Step-by-step explanation: Add 7 to both sides. We get 2x-3y=7

Now, plug in zero for y, and we are left with 2x = 7 (the y cancels.) Dividing by 2 leaves us 7/2, and (0, 7/2)

Now starting back to 2x-3y=7

Plug in zero for x, and we are legt with -3y = 7 (the x cancels.) Divide by -3, and we get -7/3 and (-7/3, 0)

8 0
2 years ago
Whats the answer ?????
wolverine [178]

46.06 would be the answer

7 0
3 years ago
Read 2 more answers
20 + 27x + 9x^2 = (?) (3x + 5)
DiKsa [7]

Answer:

(3x + 4)

Step-by-step explanation:

9x²+27x+20 can be factored out to (3x + 4)(3x + 5)

7 0
3 years ago
Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6
kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Step-by-step explanation:

Given : Equation  12x^3-5x=2x^2+x+6

We have to construct a  system of equations that  can be used to find the roots of the equation 12x^3-5x=2x^2+x+6

Consider the given equation 12x^3-5x=2x^2+x+6

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation 12x^3-5x=2x^2+x+6

becomes,

12x^3-5x=y=2x^2+x+6

Thus, The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Option (a) is correct.

   

8 0
3 years ago
Read 2 more answers
a jar contains 5 blue marbles and 3 red marbles. suppose you choose a marble at random and do not replace it. then choose a seco
lina2011 [118]
\mathbb P(R_1\cap R_2)=\mathbb P(R_2\mid R_1)\mathbb P(R_1)

The probability of drawing a red marble on the first attempt is

\mathbb P(R_1)=\dfrac{\dbinom31}{\dbinom51}=\dfrac35

After the first marble is drawn, and we know it to be red, we're drawing the next marble from a pool with one less marble than before (i.e. conditioning on the event R_1). So

\mathbb P(R_2\mid R_1)=\dfrac{\dbinom21}{\dbinom71}=\dfrac27

And so

\mathbb P(R_1\cap R_2)=\dfrac35\cdot\dfrac27=\dfrac6{35}
4 0
3 years ago
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