How would I solve for slope on an equation similar to 8x+2y=5?
2 answers:
You would isolate the y-value: 2y=5-8x and simplify into y=-4x+2.5 and that means that the slope is -4
Well make the equation into slope intercept form: y=mx + b and whatever the coefficent is to x will be your slope
8x+2y= 5 can be written as y= (-8/2)x + (5/2) so the slope would be (-8/2)
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