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2 years ago

How would I solve for slope on an equation similar to 8x+2y=5?

Mathematics

2 answers:

Kisachek [45]2 years ago

7 0

You would isolate the y-value: 2y=5-8x and simplify into y=-4x+2.5 and that means that the slope is -4

djyliett [7]2 years ago

4 0

Well make the equation into slope intercept form: y=mx + b and whatever the coefficent is to x will be your slope

8x+2y= 5 can be written as y= (-8/2)x + (5/2) so the slope would be (-8/2)

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What is the y-intercept of the equation of the line that is perpendicular to the line y =

igor_vitrenko [27]

Answer:

y=-5/3x+20

Step-by-step explanation:

Let the equation of the required line be represented as $y=mx+c$

This line is perpendicular to the line $y=\frac{3}{5}x+10$

$=>m*\frac{3}{5}=-1$

$=>m=\frac{-5}{3}$

So the equation of the required line becomes $y=\frac{-5}{3}x+c$

This line passes through the point (15.-5)

$-5=\frac{-5}{3}*15+c$

$=>c=20$

So the equation of the required line is $y=\frac{-5}{3}x+20$

Among the given options, option 4 is the correct one.

3 0

2 years ago

Factor the expression using the GCF.<br><br> 14x−98

pashok25 [27]

Answer: 14(x−7)

Hope this helps :)

8 0

3 years ago

Read 2 more answers

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

3 years ago

Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's

Anit [1.1K]

Answer:

Let the Dulcina's collection be 'x'

Let the Tremaine collection be 'x-39'

x + x - 39 =129

2x = 129 +39

2x = 168

x = 168/2

x = 84

Dulcina's collection = x = 84

Tremaine's collection = x - 39 = 84 - 39 = 45

7 0

2 years ago

H(x)=4x+3<br> Domain: all real number<br> Find range

CaHeK987 [17]

don't know if this might help but here

Step-by-step explanation:

(−∞,∞),{y|y∈R}

4 0

2 years ago