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Sati [7]
3 years ago
6

if n is a positive integer, for what values of n is the function f(x) =x to the power of n a) even b) odd

Mathematics
2 answers:
AveGali [126]3 years ago
6 0
A) n is even
b) n is odd
Otrada [13]3 years ago
5 0
f(x)=x^n;\ n\in\mathbb{Z^+}\\\\
function\ is\ even\ when\ f(-x)=f(x)\\\\function\ is\ odd\ when\ f(-x)=-f(x)\\\\a)\ f(x)\ is\ even\ when\ n\ is\ even:f(-x)=(-x)^n=x^n=f(x)\\\\b)\ f(x)\ is\ odd\ when\ n\ is\ odd:f(-x)=(-x)^n=-x^n=-f(x)
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Step-by-step explanation:

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The translation of f(x) up k units is f(x) + k

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∵ The function is  translated 3 units up

∴ k = 3

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∴ y=\frac{1}{x-5}+3

The new function is  y=\frac{1}{x-5}+3 , where x ≠ 5

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