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11Alexandr11 [23.1K]
3 years ago
8

How can you use your knowledge of minerals chemical makeup or use

Chemistry
1 answer:
yaroslaw [1]3 years ago
6 0
I would go with D on this one
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Which statement is true? Inertia causes bodies to slow in their motion, unless they’re pushed by a force. Inertia resists change
GarryVolchara [31]

Inertia  decelerates a body.
8 0
2 years ago
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PLZ HELP What human body system includes the stomach, intestines, and teeth?
andrey2020 [161]

Answer:

B

Explanation:

the digestive system

5 0
3 years ago
A sealed 1.0 l flask is charged with 0.500 mol of i2 and 0.500 mol of br2. an equilibrium reaction ensues: i2 (g) br2 (g) 2ibr (
user100 [1]

The value of Keq = 110

Let's know how to get it :


According to the equilibrium reaction equation :


I2(g) + Br2(g) → 2IBr(g)


now we need to get the value of Keq


when the Keq expression is:


Keq = [IBr]^2/ [I] [Br]


when we have [IBr] at equilibrium = 0.84 so we need to get [I] &[Br] at equilibrium .


when [Br2] = [I2] = 0.5 - 0.84 / 2


= 0.08 M


so, by substitution


∴ Keq = (0.84)^2/(0.08)^2


= 110

4 0
3 years ago
Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr
Ganezh [65]

Answer:

a. 4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

b. 146.0 g

Explanation:

Question 1 (a). Just as the problem states, liquid nitroglycerin decomposes into nitrogen gas N_2, oxygen gas O_2, water vapor H_2O and carbon dioxide CO_2. Let's write the decomposition of nitroglycerin into these 4 components:

C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + CO_2 (g)

Now we need to balance the equation. Firstly, notice we have 3 carbon atoms on the left and 1 on the right, so let's multiply carbon dioxide by 3:

C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)

Now, we have 3 nitrogen atoms on the left and 2 on the right, so let's multiply nitrogen on the right by \frac{3}{2}:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)

We have 5 hydrogen atoms on the left, 2 on the right, so let's multiply the right-hand side by \frac{5}{2}:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)

Finally, count the oxygen atoms. We have a total of 9 on the left. On the right we have (excluding oxygen molecule):

\frac{5}{2} + 6 = 8.5

This leaves 9 - 8.5 = 0.5 = \frac{1}{2} of oxygen. Since oxygen is diatomic, we need to take one fourth of it to get one half in total:

C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + \frac{1}{4} O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)

To make it look neater without fractional coefficients, multiply both sides by 4:

4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

Question 2 (b). Now we can make use of the balanced chemical equation and apply it for the context of this separate problem. We're given the following variables:

V_{CO_2} = 41.0 L

T = -14.0^oC + 273.15 K = 259.15 K

p = 1 atm

Firstly, we may find moles of carbon dioxide produced using the ideal gas law pV = nRT.

Rearranging for moles, that is, dividing both sides by RT (here R is the ideal gas law constant):

n_{CO_2} = \frac{pV_{CO_2}}{RT} = \frac{1 atm\cdot 41.0 L}{0.08206 \frac{L atm}{mol K}\cdot 259.15 K} = 1.928 mol

According to the stoichiometry of the balanced chemical equation:

4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)

4 moles of nitroglycerin (ng) produce 12 moles of carbon dioxide. From here we can find moles o nitroglycerin knowing that:

\frac{n_{ng}}{4} = \frac{n_{CO_2}}{12} \therefore n_{ng} = \frac{4}{12}n_{CO_2} = \frac{1}{3}\cdot 1.928 mol = 0.6427 mol

Multiplying the number of moles of nitroglycerin by its molar mass will yield the mass of nitroglycerin decomposed:

m_{ng} = n_{ng}\cdot M_{ng} = 0.6427 mol\cdot 227.09 g/mol = 146.0 g

3 0
3 years ago
Looking at the different chemical structures, which one(s) might be able to hold
Romashka-Z-Leto [24]

Answer:

c) Fullerene and carbon nanotubes because they have empty spaces inside the  molecules

Explanation:

Fullerene and carbon nanotubes would be the most desired in order to hold the cancer fighting drugs and to carry them through the body safely.

  • These molecules have empty spaces in them.
  • The cavities makes it possible for storage.
  • As they pass through the body, they can be held perfectly well to their target site of action.
3 0
2 years ago
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