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3 years ago

The molecule H2O can be correctly described as a?

Chemistry

1 answer:

raketka [301]3 years ago

7 0

H2o is number 2, compound and a molecule

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Silver chloride was reacted with magnesium hydroxide, in which magnesium displaced silver

Elza [17]

Answer:

<h3>The precipitate is MgCl2</h3>

Explanation:

The reaction that is described goes as follows:

2AgCl + Mg(OH)2 ---> MgCl2 + 2AgOH

The precipitate here is the MgCl2 salt.

I hope it helped!

8 0

4 years ago

Is matter smooth and continuous?

Strike441 [17]

Answer:

Explanation:

<h2><u><em> Matter is smooth and continuous. ... A liquid has a definite volume; but it has no definite shape.</em></u></h2>

3 0

3 years ago

"Tropo" is a Greek prefix meaning to change or to turn. Why is troposphere an appropriate name for the layer of atmosphere close

tia_tia [17]

Answer:

The troposphere is the layer in which weather occurs, meaning conditions are constantly changing.

Explanation:

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4 0

4 years ago

A wooden artifact from a Chinese temple has a 14C activity of 42.8 counts per minute as compared with an activity of 58.2 counts

Arlecino [84]

Answer : The age of the artifact is, $2.54\times 10^3\text{ years}$

Explanation :

Half-life = 5715 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{5715\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time taken to decay.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken by sample = ?

a = initial activity of the reactant = 58.2 counts per minute

a - x = activity left after decay process = 42.8 counts per minute

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{58.2}{42.8}$

$t=2540.5\text{ years}=2.54\times 10^3\text{ years}$

Therefore, the age of the artifact is, $2.54\times 10^3\text{ years}$

4 0

3 years ago

If the density of a certain spherical atomic nucleus is 1.0 _ 1014 g cm_3 and its mass is 2.0 _ 10_23 g, what is its radius in c

melamori03 [73]

1) Calculate the volume from d = m/V => V = m/d = 2.0*10^-23 g / 1.0*10^14 g/cm^3 = 2.0*10^-9 cm^3

2) Now use the formula of volume for a sphere: V = (4/3)π(r^3) =>

r =∛[3V/(4π)] = ∛[(3*2.0*10^-9 cm^3) / (4π)] = 0.48*10^-3 cm = 4.8*10^-4 cm = 0.00048cm

5 0

3 years ago