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liq [111]
2 years ago
5

Looking at the different chemical structures, which one(s) might be able to hold

Chemistry
1 answer:
Romashka-Z-Leto [24]2 years ago
3 0

Answer:

c) Fullerene and carbon nanotubes because they have empty spaces inside the  molecules

Explanation:

Fullerene and carbon nanotubes would be the most desired in order to hold the cancer fighting drugs and to carry them through the body safely.

  • These molecules have empty spaces in them.
  • The cavities makes it possible for storage.
  • As they pass through the body, they can be held perfectly well to their target site of action.
You might be interested in
Codons.
andrey2020 [161]

Answer:

1. C- Three.

2. A- Methionine

3. D- Translocation.

4. C- OH.

5. A - 5'

6. A - 3' carbon

7. A. adenine and guanine

Explanation:

1. A codon is a group of three nucleotide sequence that encodes or specifies an amino acid. This means that, during translation (second stage of gene expression), when a CODON is read, an amino acid is added to the growing peptide chain.

2. The codon that initiates the translation process is called a start codon. It has a sequence: AUG and it specifies Methionine amino acid. Hence, during translation where a tRNA binds to the mRNA codon to read it and add its corresponding amino acid, a tRNA with a complementary sequence of AUG (start codon) binds to it and carries Methionine amino acid.

3. Translocation is a process during translation whereby the mRNA-tRNA moeity moves forward in the ribosome to allow another codon to move into the vacant site for translation process to continue.

4. The sugar component of a nucelotide that makes up the nucleic acid (DNA or RNA) i.e. ribose or deoxyribose, contains an hydroxyll functional group (-OH).

5. A nucleotide consists of a pentose (five carbon) sugar, phosphate group and a nitrogenous base. The phosphate group (PO43-) is attached to the 5' carbon of the sugar molecule.

6. The free hydroxyll group (-OH) of the five carbon sugar molecule in DNA is attached to its 3' carbon.

7. Nitrogenous bases are the third component of a nucleotide, the other two being pentose sugar and phosphate group. The nitrogenous bases are four viz: Adenine, Guanine, Cytosine, and Thymine. These bases are classified into Purines and Pyrimidines based on the similarity in their structure. Adenine (A) and Guanine (G) are Purines because they possess have two carbon-nitrogen rings, as opposed to one possessed by Pyrimidines (Thymine and Cytosine).

7 0
3 years ago
9 Cardiac disease is a major problem in the United States."
amid [387]

Answer:

D It affects the heart

Explanation:

5 0
3 years ago
Use the value of the Avogadro constant (6.02 × 1023 mol–1) to calculate the total number of atoms in 7.10 g of chlorine atoms. (
kolbaska11 [484]

The total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.

HOW TO CALCULATE NUMBER OF ATOMS:

  • The number of atoms in a substance can be calculated by multiplying the number of moles in that substance by Avogadro's number as follows:

  • no. of atoms = no. of moles × 6.02 × 10²³ mol-¹

  • The number of moles in 7.10g of Cl is calculated as follows:

no. of moles = mass ÷ molar mass

no. of moles = 7.10g ÷ 35.5g/mol

no. of moles = 0.2mol

no of atoms = 0.2mol × 6.02 × 10²³

no. of atoms = 1.204 × 10²³atoms.

  • Therefore, the total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.

Learn more: brainly.com/question/15488332?referrer=searchResults

6 0
2 years ago
What are two ways carbon returns from animal into the water
soldi70 [24.7K]
Split and merge into it. While they are alive, carbon returns from animals into water through waste products from respiration and defecation/urination. Another way when they are dead is from decaying remains. While they are alive, carbon returns from animals into water through waste products from respiration and defecation/urination.

Good enough?
8 0
3 years ago
What is the molarity of a 250.0 milliliter aqueous solution of sodium hydroxide that contains 15.5 grams of solute? 6.2 M
Alchen [17]
Moles = 15.5 g / 40 g/mol = 0.3875 mol

M = 0.3875 mol / 0.250 L = 1.55M
8 0
3 years ago
Read 2 more answers
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