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olga2289 [7]
3 years ago
12

3. Name the property on which floating and sinking of a body depends.​

Chemistry
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

body mass index

Explanation:

it is the property by which the floating and sinking of body depends

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How many atoms are in the 1.5 moles of tin atoms?
Anastasy [175]

Answer:

option C = 9.0 x 10²³ atoms

Explanation:

Data Given:

no. of moles of tin (Sn) atoms = 1.5 moles

no. of tin (Sn) atoms = ?

Solution:

Formula used to find number of atoms

                  no. of moles = no. of atoms / Avogadro's number

Rearrange the above equation:

          no. of atoms =   no. of moles x Avogadro's number . . . . . . (1)

Where

Avogadro's number = 6.022 x 10²³

Put values in equation 1

           no. of atoms = 1.5 x 6.022 x 10²³

           no. of atoms = 9.033 x 10²³

Round the figure = 9.0 x 10²³ atoms

So option C is correct

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Can I find the state of Ca3N2 using the solubility rules? If so how because there is no Nitride in the solubility tables, I don'
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What is mass????????????????????
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Do you need the definition or the equation to find it?

Explanation:

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What was formed when you dropped the rock to the sand?
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Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of
shusha [124]

Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}

For the oxygen:

81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

\frac{0.81}{2}=0.41

For the oxygen:

\frac{2.54}{19}=0.13

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}

7 0
3 years ago
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