1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sasho [114]
4 years ago
15

What is the length of AC?

Mathematics
1 answer:
ivanzaharov [21]4 years ago
7 0
It's 7.3
To find the ratio divide 14.04 by 5.2
Then check another one, divide 21.87 by 2.7 and 19.87 by 2.7 to get the other two sides.
You might be interested in
Which of the following is true because of the commutative law of multiplication
kap26 [50]
<h3>Answer: Choice C</h3>

Explanation:

The commutative law of multiplication says that A*B = B*A, for any real numbers A,B. The order of multiplication doesn't matter.

That's why 15*3 is the same as 3*15.

This is because having 15 groups of 3 leads to 3+3+3+...+3 = 45 (imagine adding 15 copies of '3' together), and having 3 groups of 15 gets us 15+15+15 = 45 as well.

Or you could picture a rectangular table that has 15 rows and 3 columns. It has 45 inner cells. If the table had 3 rows and 15 columns, then we'd still have 45 inner cells.  

6 0
3 years ago
How do solve this please!!!! ASAP
Semmy [17]

Answer:

tan 43 = x/12

x = 12•tan 43

x = 12 × 0.9325

x = 11.19

3 0
4 years ago
There is a total of 100 calories in 15 of Mei's favorite crackers. What is
borishaifa [10]

Answer:

2,100

Step-by-step explanation:

first you want divide 140 by 20 to find the the amount of calories per cracker so 140 divided by 20 is 7 then all you need to do is multiply 7 time the 300 crackers to get you total of 2,100.

-----------------------------------------------------------------------------------------------------------------

Hope it helps! 0.0

6 0
3 years ago
Read 2 more answers
PLEASE PLEASE HELP
nata0808 [166]

Answer:

Step-by-step explanation:

we cant see it

6 0
3 years ago
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
Other questions:
  • Solve the following equation for the value of d.
    15·1 answer
  • A=2πr^2+2πrh solve for π
    15·1 answer
  • 10<br> If m 2 = 148°, what is the measure<br> of 28?<br><br> 32<br> 64<br> 148<br> 180°
    6·1 answer
  • An experiment consists of drawing 1 card from a standard​ 52-card deck. What is the probability of drawing a jack?
    5·1 answer
  • How do you find the IQR? *
    10·1 answer
  • I need help with this?? Anyone?
    9·2 answers
  • 100 x 100 divided by 500 x 400 x 10 divided by 600
    11·1 answer
  • Mary bought 4 small cookies for 40 cents each and 2 large cookies for 90 cents each how much did she spend all together
    5·1 answer
  • Nick estimates that 50% of his income goes toward living expenses. Of the rest 50% goes to paying for his car and 25% of what is
    14·1 answer
  • How much green ooze was carried in all I I'll send the picture
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!