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4 years ago

Which statement is true of an activated complex formed during a chemical reaction?

Chemistry

2 answers:

Vladimir [108]4 years ago

7 0

Answer:

It is only formed in the forward direction.

Explanation:

Activated complex is formed by the combination of reactant molecules. Activated complex is formed only in the forward reaction and not in the backward reaction. Option C is correct.

It has the highest energy in the potential energy diagram. Activated complex is known as the transition state and does not include any product molecules. Option D is incorrect.

Option A is incorrect as an activated complex may contain most if not all of the atoms of a reactant particle.

Option B is incorrect as an activated complex is only a transitions state which is unstable and it changes to form products which are more stable.

sergey [27]4 years ago

6 0

I think the correct answer among the choices presented above is the third option. An activated complex formed during a chemical reaction is only formed in the forward direction. It is a temporary unstable compound formed when the activation energy of a reaction is attained.

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natka813 [3]

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2 years ago

A chemist wishing to do an experiment requiring 47Ca2+(half-life = 4.536 days) needs 5.00 g of the nuclide. What mass of 47CaCO

Artyom0805 [142]

Answer: The answer is 6.78 grams.

Explanation: The equation used for solving this type of problems is:

$\frac{N}{N_0}=(\frac{1}{2})^n$

where, $N_0$ is the initial amount of radioactive substance, N is the remaining amount and n is the number of half lives.

Number of half lives is calculated on dividing the given time by the half life.

n = time/half life

Time is given as 48.0 hours and the half life is given as 4.536 days. let's make the units same and for this let's convert the half life from days to hours.

$4.536days(\frac{24hours}{1day})$

= 108.864 hours

So, $n=\frac{48.0}{108.864}$ = 0.441

Since 5.00 g is the required amount when the radioactive substance is delivered to the scientist, it would be the final amount that is N. We need to calculate the initial amount. Let's plug in the values in the equation:

$\frac{5.00}{N_0}=(\frac{1}{2})^0^.^4^4^1$

$\frac{5.00g}{N_0}=0.737$

$N_0=\frac{5.00g}{0.737}$

$N_0$ = 6.78 g

So, 6.78 g of the radioactive substance needs to be ordered.

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4 years ago

If there were 10 grams of a radioactive isotope, how much of the sample would be left after 1 half-life? How much after 2 half-l

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3 years ago

A sample of water in equilibrium with its vapor in a closed 3-L container has a vapor pressure of 23.8 torr at 25°C. The contain

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Answer:

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Explanation:

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Answer:

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