The answer is:
172 cm squared
Working out/ Explanation:
13 times 4 = 52
7 times 6 = 42
26 times 3 = 78
52+42+78= 172
Hope this helps!
Please give Brainliest!
20% = 2/10 or 1/5 (simplest form)
There is nothing to solve y=x
Answer:
Help
Step-by-step explanation:
I how can I help you?
Answer:
The percentage of admitted applicants who had a Math SAT of 700 or more is 48.48%.
Step-by-step explanation:
The Bayes' theorem is used to determine the conditional probability of an event <em>E</em>
, belonging to the sample space S = (E₁, E₂, E₃,...Eₙ) given that another event <em>A</em> has already occurred by the formula:
![P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\limits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}](https://tex.z-dn.net/?f=P%28E_%7Bi%7D%7CA%29%3D%5Cfrac%7BP%28A%7CE_%7Bi%7D%29P%28E_%7Bi%7D%29%7D%7B%5Csum%5Climits%5E%7Bn%7D_%7Bi%3D1%7D%7BP%28A%7CE_%7Bi%7D%29P%28E_%7Bi%7D%29%7D%7D)
Denote the events as follows:
<em>X</em> = an student with a Math SAT of 700 or more applied for the college
<em>Y</em> = an applicant with a Math SAT of 700 or more was admitted
<em>Z</em> = an applicant with a Math SAT of less than 700 was admitted
The information provided is:
![P(Y)=0.36\\P(Z)=0.18\\P(X|Y)=0.32](https://tex.z-dn.net/?f=P%28Y%29%3D0.36%5C%5CP%28Z%29%3D0.18%5C%5CP%28X%7CY%29%3D0.32)
Compute the value of
as follows:
![P(X|Z)=1-P(X|Y)\\=1-0.32\\=0.68](https://tex.z-dn.net/?f=P%28X%7CZ%29%3D1-P%28X%7CY%29%5C%5C%3D1-0.32%5C%5C%3D0.68)
Compute the value of P (Y|X) as follows:
![P(Y|X)=\frac{P(X|Y)P(Y)}{P(X|Y)P(Y)+P(X|Z)P(Z)}](https://tex.z-dn.net/?f=P%28Y%7CX%29%3D%5Cfrac%7BP%28X%7CY%29P%28Y%29%7D%7BP%28X%7CY%29P%28Y%29%2BP%28X%7CZ%29P%28Z%29%7D)
![=\frac{(0.32\times 0.36)}{(0.32\times 0.36)+(0.68\times 0.18)}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%280.32%5Ctimes%200.36%29%7D%7B%280.32%5Ctimes%200.36%29%2B%280.68%5Ctimes%200.18%29%7D)
![=0.4848](https://tex.z-dn.net/?f=%3D0.4848)
Thus, the percentage of admitted applicants who had a Math SAT of 700 or more is 48.48%.