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11Alexandr11 [23.1K]
3 years ago
15

What were the 3 common states of matter on Earth?

Chemistry
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

i think that the answer is solid liquid and gas.

Explanation:

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The air we breathe is not considered by chemists to be an element. why not
ohaa [14]
Because Air itself is not an element. it is made up by different elements such as Oxygen and nitrogen. since its made up of a mix of different elements, its rather a homogeneous mixture :)
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3 years ago
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What do the subscripts in the formula for ethane represent?
Sedaia [141]

Answer:

the number of carbon and hydrogen atoms present in the molecule of Ethane that is it contains two carbon atoms and six hydrogen atoms

Explanation:

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3 years ago
What results when two waves that are completely out of phase meet?
ELEN [110]

Answer:

The result is a superposition which is twice the amplitude of each input wave. Φ = π means the two waves are completely OUT OF PHASE, and so add completely destructively. The result is a superposition which has no amplitude at all.

Explanation:

The result is a superposition which is twice the amplitude of each input wave. Φ = π means the two waves are completely OUT OF PHASE, and so add completely destructively. The result is a superposition which has no amplitude at all.

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1 year ago
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Predict the products when cyclohexanol is dehydrated.
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5 0
3 years ago
Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

6 0
3 years ago
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