2LiI+1Br₂-->2LiBr+1I₂
1CsNO₃+1KCl-->1CsCl+1KNO₃
V1 = 2.00 L
<span>T1 = 25 + 273 = 298 K </span>
<span>V2 = 6.00 L </span>
<span>T2 = ? </span>
<span>Assuming the pressure is to remain constant, then </span>
<span>V1/T1 = V2/T2 </span>
<span>T2 = T1V2/V1 = (298)(6)/(2) = 894 deg K</span>
If 0.25mg of atropine is in 1mL
so
0.50mg of atropine is in x