Answer:
20N
Explanation:
Given parameters:
Force(N) Acceleration(m/s²)
10 0.2
? 0.4
Unknown:
The force applied when the acceleration is 0.4m/s²
Solution:
From newton's second law of motion;
Force = mass x acceleration
Since we are using the same box, let us find the mass of the box;
Force = mass x acceleration
10 = mass x 0.2
mass =
= 50kg
Now,
The force in the second instance will be;
Force = 50 x 0.4 = 20N
Answer:
D
Explanation:
D is the answer because 2 is needed to know
Answer:
As for your question, I know to forget to put the options, specifically that your question is incomplete.
Explanation:
Although it could help you by telling you that always a reaction that seeks to balance the pH, and achieve neutrality ... It is necessary to achieve a concentration of OH equal to that of H +, in this way the hydroxyl and the protons.
Answer:
The correct answer is option C.
Explanation:

On increasing the pH of the blood the hydronium ions concentration will decrease which will result in decrease in concentration of hydronium ions at the equilibrium state of hydrogen carbonate.
Le-Chatelier's principle:
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
According to Le-Chatelier's principle , on decrease in a concentration of the product the equilibrium moves in forward correction to re-establish itself.
So, on increasing the pH, the hydronium ions concentration will decrease which results in disassociation of more hydrogen carbonate to maintain the pH of the blood.
Hence, the correct answer is option C.
Answer:
A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH
Explanation:
The pH of a buffer solution is calculated using following relation

Thus the pH of buffer solution will be near to the pKa of the acid used in making the buffer solution.
The pKa value of HC₃H₅O₃ acid is more closer to required pH = 4 than CH₃NH₃⁺ acid.
pKa = -log [Ka]
For HC₃H₅O₃
pKa = 3.1
For CH₃NH₃⁺
pKa = 10.64
pKb = 14-10.64 = 3.36 [Thus the pKb of this acid is also near to required pH value)
A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH
Half of the acid will get neutralized by the given base and thus will result in equal concentration of both the weak acid and the salt making the pH just equal to the pKa value.