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Oliga [24]
2 years ago
9

What are the reactants of cellular respiration? Check all that apply

Chemistry
2 answers:
iris [78.8K]2 years ago
8 0

Answer:

c and d

Explanation:

i did the assignment and got a 100 when i put those 2  

Clair
2 years ago
YOU WRONG FUCKING BITCH
Clair
2 years ago
Its B AND C
ryzh [129]2 years ago
4 0

Answer:

Glucose and oxygen

Explanation:

First, let's look at the cellular respiration equation:

glucose+oxygen--> carbon dioxide+water+ATP (energy)

The reactants are what go in to make the products. In this case, glucose and oxygen are used to make carbon dioxide, water, and ATP. Therefore, glucose and oxygen are the reactants. Carbon dioxide, water and ATP are the products.

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Convert 3.52 × 10^22 atoms of gold to moles​
IrinaVladis [17]

Answer:

5.85 x 10⁻² mol Au

Explanation:

Divide the atoms of gold with Avogadro's number to find the solution.

5 0
2 years ago
Describe the position of metal ,non metals and metollieds in perodic tables​
siniylev [52]
Non metals and metollids in periodic tables are the same how this helps ;)
4 0
3 years ago
An atom of 40 18 Ar has a nucleus that contains a total of
Cloud [144]
The correct answer is b, 18 protons
4 0
3 years ago
Read 2 more answers
two sides of a triangle have the following measures . Find The range of possible measures for the tird side
crimeas [40]
To find the third side you would use Pythagorean theorem which is a²+b²=c². 

A and B being the 2 legs and C being the hypotenuse.
 
Example: ( sorry for the really odd not really a triangle, triangle...)
  |  \
6|     \  ?                    6²+9²=C²
  |_______              36+81=C²
        9                             117=C²
                               √117=10.8 (rounded) 

if you need to get the leg you just fill in the numbers.



3 0
2 years ago
Calculate the mass of xenon difluoride gas with a volume of 0.223 L, pressure of 0.799 atm and temperature of 47.0 oC.
Greeley [361]

The mass of the gases can be determined by the moles of the gas in the ideal equation. The mass of xenon difluoride at 0.799 atm is 0.011 gms.

<h3>What is an ideal gas equation?</h3>

An ideal gas equation gives the moles of the substance from the temperature, volume, and pressure of the gas. The ideal gas equation can be shown as:

n = PV ÷ RT

Here, n = mass ÷ molar mass

Given,

Volume of xenon difluoride (V) = 0.223 L

Pressure of xenon difluoride (P) = 0.799 atm

Temperature of xenon difluoride (T) = 320.15 Kelvin

Gas constant (R) = 8.314 J⋅K⁻¹⋅mol⁻¹

The moles of the gas is calculated as:

n = PV ÷ RT

= 0.223 × 0.799 ÷ 8.314 × 320.15

= 0.1781 ÷ 2661.72

= 6.69 × 10⁻⁵ moles

Mass is calculated as:

169.29 × 6.69 × 10⁻⁵ = 0.011 gm

Therefore, 0.011 gms is the mass of xenon difluoride.

Learn more about ideal gas here:

brainly.com/question/14189621

#SPJ1

8 0
2 years ago
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