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Oliga [24]
3 years ago
9

What are the reactants of cellular respiration? Check all that apply

Chemistry
2 answers:
iris [78.8K]3 years ago
8 0

Answer:

c and d

Explanation:

i did the assignment and got a 100 when i put those 2  

Clair
2 years ago
YOU WRONG FUCKING BITCH
Clair
2 years ago
Its B AND C
ryzh [129]3 years ago
4 0

Answer:

Glucose and oxygen

Explanation:

First, let's look at the cellular respiration equation:

glucose+oxygen--> carbon dioxide+water+ATP (energy)

The reactants are what go in to make the products. In this case, glucose and oxygen are used to make carbon dioxide, water, and ATP. Therefore, glucose and oxygen are the reactants. Carbon dioxide, water and ATP are the products.

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How would the electron configuration of nitrogen change to make a stable configuration?
AnnZ [28]

The answers to the questions are as follows;

  1. It would gain three electrons
  2. The difference in their electronegativities.
  3. The elements have filled Valence levels
  4. potassium (K) with a 1+ charge
  5. ClO-

Question 1:

  • How would the electron configuration of nitrogen change to make a stable configuration?

Since Nitrogen has 5 Valence electrons, it needs 3 electrons to attain it's octet configuration. As such, it gains 3 electrons.

Question 2:

  • Which quantity determines how two atoms bond.

The quantity which determines how two atoms bond is The difference in their electronegativities.

Question 3:

  • Which statement best explains why the elements in Group 18 do not have electronegativity values.

This is because the elements have filled Valence levels.

Question 4:

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The ion which has a stable Valence electron configuration is potassium (K) with a 1+ charge

Question 5;

  • Which chemical formula represents a polyatomic ion?

The chemical formula which represents a polyatomic ion is; ClO-

5 0
3 years ago
A sample of nitrogen gas occupies 1.55 L at
34kurt

Answer:

The new volume after the temperature reduced to -100 °C is 0.894 L

Explanation:

Step 1: Data given

Volume of nitrogen gas = 1.55 L

Temperature = 27.0 °C = 300 K

The temperature reduces to -100 °C = 173 K

The pressure stays constant

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of the gas = 1.55 L

⇒with T1 = the initial temperature = 300 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the reduced temperature = 173 K

1.55 L / 300 K = V2 / 173 K

V2 = (1.55L /300K) * 173 K

V2 = 0.894 L

The new volume after the temperature reduced to -100 °C is 0.894 L

3 0
3 years ago
Latoya performs an experiment using the lab equipment shown. Which two properties is Latoya most likely measuring?
spayn [35]

Answer: Volume and temperature

Explanation:

5 0
3 years ago
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What is the V2O5 coefficient??
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Answer:

1235

Explanation:

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