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ad-work [718]
2 years ago
15

The average atomic mass of a sample of an element X is 16.2u. What are the percentages of isotopes X (mass number 16, atomic num

ber 8) and X (mass number 16, atomic number 8) in the sample?
Chemistry
1 answer:
belka [17]2 years ago
8 0

Answer:

isotopes of hydrogen are protium,deuterium and tritium

You might be interested in
21.7 mL of gas at 98.8 kPa is allowed to expand at constant
IRISSAK [1]

Answer: 40.68 kPa

Explanation:

Given that,

Original volume of gas V1 = 21.7 mL

Original pressure of gas P1 = 98.8 kPa

New volume of gas V2 = 52.7 mL

New pressure of gas P2 = ?

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

98.8 kPa x 21.7 mL = P2 x 52.7L

2143.96 kPa L = 52.7 L x P2

P2 = 2143.96 kPa L / 52.7 L

P2 = 40.68 kPa

Thus, the new pressure of the gas is 40.68 kPa.

5 0
3 years ago
This is what the enzyme looks like at 4C
Art [367]

Answer:

molecular diagram 3 or 2 is correct answer I hope it helps you

5 0
2 years ago
The picture is a waning gibbous. What phase will the moon be two weeks later?
SVETLANKA909090 [29]

Answer:

d

Explanation:

5 0
3 years ago
Read 2 more answers
Medicinal “ether" is produced when ethyl alcohol is treated with an acid. How many grams of
DochEvi [55]

Answer:

34.3 g

Explanation:

Step 1: Write the balanced equation

2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O

Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH

The molar mass of CH₃CH₂OH is 46.07 g/mol.

50.0 g × 1 mol/46.07 g = 1.09 mol

Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced

The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.

Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced

The percent yield of the reaction is 85%.

0.545 mol × 85% = 0.463 mol

Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃

The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.

0.463 mol × 74.12 g/mol = 34.3 g

6 0
3 years ago
A roller coaster starts down a hill at 10 m/s. Three seconds later, its speed is 32 m/s. What is the roller coaster’s accelerati
erica [24]
Final velocity(v) = 32 m/s
Initial velocity(u) = 10 m/s

Using kinematic equation v = u + at, 

32 = 10 + a(3)

32-10
---------  = a
    3

a = 22
      ----
       3

a = 7.3 m/s^2.

Hence acceleration of the roller coaster is 7.3 m/s^2.

Hope this helps!!
8 0
3 years ago
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