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Wewaii [24]
3 years ago
13

The Kp for the reaction below is 1.49 × 108 at 100.0°C:

Chemistry
1 answer:
Anna007 [38]3 years ago
5 0
Kp= (COCl2)/[(CO)(Cl2)]= 1.49 x 10^8

1.49 x 10^8= (COCl2/((2.22x10-4)(2.22x10-4))

COCl2= 1.49x10^8 x ((2.22x10-4)(2.22x10-4))= 7.34 atm
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<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

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