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tekilochka [14]
3 years ago
5

Which of the following conditions increases the frequency of collisions without changing the energy or concentration of reactant

s?
A: increasing the surface area of the substance
B: adding more reactant molecules
C: increasing the temperature
D: increasing the pressure
Chemistry
2 answers:
Brums [2.3K]3 years ago
5 0
You can promote collisions between molecules when you increase their kinetic energy by either increasing the temperature or pressure conditions of the systems. However, it is indicated that you must not change the energy. So, we eliminate choices C and D. Choice B is contradictory to the limitation that you do not increase the concentration of the reactants. Technically, all of the choices promote frequent collisions. But due to the limitations set, the accepted answer is letter A. When you increase the surface area by using powdered reactants instead of cubes, you increase the areas for susceptibility of collisions.
ladessa [460]3 years ago
3 0

Answer:

A: increasing the surface area of the substance

Explanation:

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The concentration of glucose inside a cell is 0.12 mM. Outside the cell the concentration of glucose is 12.9 mM. Calculate the c
Alenkasestr [34]

Answer:

The value of he change in Gibbs free energy ΔG = - 18.083 KJ

Explanation:

Given data

The concentration of glucose inside a cell is (P) = 0.12 m M

The concentration of glucose outside a cell is (R) = 12.9 m M

No. of  moles = 1.5 moles

The change in Gibbs free energy

ΔG = RT ㏑\frac{P}{R}

ΔG = 8.314 × 310 ㏑\frac{0.12}{12.9}

ΔG = - 12.055 \frac{J}{mole}

Since No. of  moles = 1.5 moles

Therefore

ΔG = - 12.055 × 1.5

ΔG = - 18.083 KJ

This the value of he change in Gibbs free energy.

7 0
3 years ago
Complete the sentences to explain your reasoning.
vredina [299]

Answer:

1-b

2-weaker(option is incorrect)

3-a

Explanation:

1-b because iodine is more electronegative because of this negative on iodine will be more stable as negative charge on more electronegative element is more stable.

2-weaker as size of Te (Tellurium) is greater than S (sulphur) so bond length of H-Te is larger than H-S and therefore bond energy will be lesser and can easily give hydrogen in case of H-Te. as bond energy is inversly proportional to bond length.

3-a hydrogen has more negative electron affinity so hydrogen will have -1 charge and it will behave as a electron donar atom that is basic not acidic hence NaH is not acidic.

3 0
3 years ago
Choose all the statements that are true for Relative Age Dating.
Lorico [155]

Answer:

Which one goes in the absolute dating column, relative column, and both.

Lesson 4.07: Relative and Absolute Dating DIRECTIONS: Use the facts below to complete the chart for Relative and Absolute Dating.

1. The Law of Superposition – the age of an object may be determined by the depth at which it is found, the deeper the object is in the Earth, the older it is.

2. Gives scientist an exact age of a rock fossil.

3. Scientist use their knowledge of the half-life of carbon and uranium isotopes to measure the age of the rock or fossil .

4. Used to determine the age of an object, when there is no record of a living thing.

5. Gives the approximate age of a fossil or artifact.

6. Used by scientist to determine the age of a fossil or artifact.

7. Estimates the order of geological or prehistoric events, but cannot be used to determine when these events have occurred.

8. Measures the decay of a rock or fossil to measure the age.

3 0
2 years ago
How many significant figures<br> are in this number?<br> 43.55
leva [86]

Answer:

4 significant figures

Explanation:

Significant figures are the units/digits within a number that make the number more accurate and precise.

All digits (except for 0) are always significant. Therefore, all the digits in 43.55 are significant. Since there are 4 digits in the given number, there are 4 significant figures.

7 0
2 years ago
How many moles of methane occupy a volume of 2.00 l at 50.0°c and 0.500 atm answer?
Sauron [17]
Data Given:
                  Pressure  =  P  =  0.5 atm
 
                  Volume  =  V  =  2.0 L

                  Temperature  =  T  =  50 °C + 273  =  323 K

                  Moles  =  n  =  ?

Solution:
              Let suppose the gas is acting Ideally, Then According to Ideal Gas Equation.

                              P V  =  n R T
Solving for n,
                              n  =  P V / R T

Putting Values,
                             n  =  (0.5 atm × 2.0 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 323 K)

                             n  =  0.0377 mol
5 0
3 years ago
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