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Ira Lisetskai [31]
4 years ago
12

How many electrons must be removed from an electrically neutral silver dollar to give it a charge of +3.5x10^-6C?

Physics
1 answer:
san4es73 [151]4 years ago
3 0

Answer:

2.19\cdot 10^{13}

Explanation:

The electron is a fundamental particle, with a charge of

e=-1.6\cdot 10^{-19}C

which is also known as fundamental charge.

For an object having N excess electrons, the total charge on the object is

Q=Ne (1)

where e is the charge of the electron.

For the object in this problem, its charge is

Q=+3.5\cdot 10^{-6} C

This can be obtained by removing a negative charge equal to

Q=-3.5\cdot 10^{-6}C

Substituting into (1) and solving for N, we can find the number of electrons:

N=\frac{Q}{e}=\frac{-3.5\cdot 10^{-6}}{-1.6\cdot 10^{-19}}=2.19\cdot 10^{13}

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A common cylindrical copper wire used in a lab is 841 m long. Find the radius (in mm) of a wire necessary to have 0.5 Ohms of re
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The relationship between the resistance R of a wire and its resistivity \rho is given by
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In the problem, we have R=0.5 \Omega, \rho = 1.68 \cdot 10^{-8} \Omega m and L=841 m. So we can solve the find the area A:
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