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Allushta [10]
2 years ago
6

Please help with the circled questions for my study guide need help asap

Physics
1 answer:
irina1246 [14]2 years ago
5 0
<h3>Answer: A voltmeter is connected in parallel with a device to measure its voltage, while an ammeter is connected in series</h3>

Explanation: okay for question B its

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In optics, a diffraction ___________ is an optical component with a periodic structure, which splits and diffracts light into se
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If a 2.0Ω resistor and a 4.0Ω resistor are connected with a 12 volt battery, what is the total resistance of the circuit?
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6 ohms

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3 0
3 years ago
Ezra (m = 20.0 kg) has a tire swing and wants to swing as high as possible. He thinks that his best option is to run as fast as
Dmitriy789 [7]

Answer:

a) v=5.6725\,m.s^{-1}

b) h= 1.6420\,m

Explanation:

Given:

  • mass of the body, M=20\,kg
  • mass of the tyre,m=10\,kg
  • length of hanging of tyre, l=3.5m
  • distance run by the body, d=10m
  • acceleration of the body, a=3.62m.s^{-2}

(a)

Using the equation of motion :

v^2=u^2+2a.d..............................(1)

where:

v=final velocity of the body

u=initial velocity of the body

here, since the body starts from rest state:

u=0m.s^{-1}

putting the values in eq. (1)

v^2=0^2+2\times 3.62 \times 10

v=8.5088\,m.s^{-1}

Now, the momentum of the body just before the jump onto the tyre will be:

p=M.v

p=20\times 8.5088

p=170.1764\,kg.m.s^{-1}

Now using the conservation on momentum, the momentum just before climbing on the tyre will be equal to the momentum just after climbing on it.

(M+m)\times v'=p

(20+10)\times v'=170.1764

v'=5.6725\,m.s^{-1}

(b)

Now, from the case of a swinging pendulum we know that the kinetic energy which is maximum at the vertical position of the pendulum gets completely converted into the potential energy at the maximum height.

So,

\frac{1}{2} (M+m).v'^2=(M+m).g.h

\frac{1}{2} (20+10)\times 5.6725^2=(20+10)\times 9.8\times h

h\approx 1.6420\,m

above the normal hanging position.

3 0
3 years ago
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