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1 year ago

While working out, a man performed 500 J of work in 8 seconds. What washis power?A. 4000 WB. 62.5 WC. 500 WD. 38.5 W

Physics

1 answer:

Sav [38]1 year ago

5 0

Given:

The work done by the man is W = 500 J

The time taken by the man is t = 8 s

To find the power.

Explanation:

The power can be calculated by the formula

$P=\frac{W}{t}$

On substituting the values, the power will be

$\begin{gathered} P=\text{ }\frac{500}{8} \\ =\text{ 62.5 W} \end{gathered}$

Thus, the power is B. 62.5 W

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2 years ago

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Answer:

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a. Fnet= F1+F2+F3

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Fnet= -2.04i+37.62j

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Fnet= √((-2.04)^2+(37.62)^2)

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Fnet is approximately 38N.

b. Direction of the Fnet.

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Angle=arctan(-37.61/2.04)

Angle= -43.37°

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3 years ago

A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres

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Answer:

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putting all value

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3 years ago

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height of the block,h = 0.31 m

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