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Harrizon [31]
3 years ago
5

BRAINLIEST ASAP! PLEASE HELP ME :)

Mathematics
2 answers:
Mariana [72]3 years ago
5 0

Answer:

Yes, the given measures can be the lengths of the sides of a triangle.

Step-by-step explanation:

hope this helps

Lerok [7]3 years ago
5 0

Answer:

Yes; the sum of any two sides is greater than the third.

Step-by-step explanation:

Longest side < sum of two shorter sides

19.1 < 8.5 + 13

19.1 < 21.5 is a true statement

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Determine if the sequence is arithmetic. If it is, find the common difference.
Margaret [11]

Answer:

1) Arithmetic since it decreases by 3 so, -3n + 38.

2) Arithmetic since it decreases by 20 each time, so -20n+17

Step-by-step explanation:

4 0
1 year ago
Please Help 11th Grade Math ASAP<br> It is really hard so I need someone really smart.
Zolol [24]

Answer:

i am in 7th grade

Step-by-step explanation:

6 0
3 years ago
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What is the greatest common factor of 39 and 6
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3 years ago
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The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000​
Papessa [141]

Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

:

We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

Ao = initial amt (t=0)

t = time period in question

d = doubling time of substance

In our problem

d = 15 min

t = 90 min

A = 50000

What was the initial population at time t = 0

Ao * 2^(90/15) = 50000

Ao * 2^6 = 50000

We know 2^6 = 64

64(Ao) = 50000

Ao = 50000/64

Ao = 781.25 is the initial population

:

Find the size of the bacterial population after 4 hours

Change 4 hr to 240 min

A = 781.25 * 2^(240/15

A = 781.25 * 2^16

A= 781.25 * 65536

A = 51,199,218.75 after 4 hrs

6 0
3 years ago
If 3220 = 80+7, what is the value of c?
Setler79 [48]

Answer:

Correct option is

C

36.25

Modal class =30−40

So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒  Mode=l+2f1−f0f2f1−f0×h

                  =30+2×32−12−2032−12×10

                  =30+6.25

                  =36.25

∴  Mode =36.25

8 0
2 years ago
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