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sashaice [31]
2 years ago
5

Fairly easy question

Mathematics
1 answer:
nexus9112 [7]2 years ago
7 0

Answer:

C. x=3 and y=−6

Step-by-step explanation:

Step: Solvex−2y=15for x:

x−2y=15

x−2y+2y=15+2y(Add 2y to both sides)

x=2y+15

Step: Substitute2y+15forxin2x+4y=−18:

2x+4y=−18

2(2y+15)+4y=−18

8y+30=−18(Simplify both sides of the equation)

8y+30+−30=−18+−30(Add -30 to both sides)

8y=−48

8y8=−488(Divide both sides by 8)

y=−6

Step: Substitute−6foryinx=2y+15:

x=2y+15

x=(2)(−6)+15

x=3(Simplify both sides of the equation)

Answer:

x=3 and y=−6

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Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
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Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

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A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

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