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2 years ago

The length of a rectangle is twice its width. If the perimeter of the rectangle is 54 in, find its area.

Mathematics

2 answers:

sergiy2304 [10]2 years ago

6 0

Answer: 162 in²

Step-by-step explanation:

The factors of 54 are listed below:

18 and 9 are the two factors that when plugged into the equation below, equals 54:

$l+l+w+w=P$

This can also be written as:

$(l*2)+(w*2)=P$

So now that we have our two factors, we need to multiply them by each other to get our answer.

18 times 9 = 162

Our answer is 162

gladu [14]2 years ago

5 0

Answer:

a= 162 sq.m

Step-by-step explanation:

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AysviL [449]

3. -x²+-4x+-8

To solve:

−4x−5+−1(x²+3)

−4x+−5+−1x²+(−1)(3)

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Combine like terms.

−4x+−5+−x²+−3

(−x²)+(−4x)+(−5+−3)

It is not in standard form since this answer does NOT have x=, y=, #=. It only has the numbers. So, this is NOT in standard form.

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3 years ago

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swat32

Answer:

180

Step-by-step explanation:

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3 years ago

S a punishment for something naughty that we did, my little brother and I have to whitewash both sides of a fence. We start at t

Step2247 [10]

Two and a half hours.

8 0

3 years ago

Let <img src="https://tex.z-dn.net/?f=K" id="TexFormula1" title="K" alt="K" align="absmiddle" class="latex-formula"> be a circle

yan [13]

The bisector of angle APQ passes through O and this is illustrated below.

<h3>How to illustrate the information?</h3>

From the information given, the center is O. and the circle passes through O and cuts at K.

In this case, it should be noted that the circles are equal according to the SAS test.

Here, AOB + APQ = 180° (Linear pair)

2AOB = 180

AOB = 90.

Therefore, the bisector of angle APQ passes through O.

Learn more about bisector on:

brainly.com/question/11006922

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8 0

2 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

3 years ago