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ivanzaharov [21]
3 years ago
8

I need help on this ​

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

The answer for this problem is 6300

Alla [95]3 years ago
5 0

Answer:

3,024,000 over 480 = 6300

Hope this helps

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The package shown is shaped like a right rectangular prism. Every side of the package will be covered with gift wrap, except the
Alexxandr [17]
<span> three-dimensional figure has length, width, and height. A face is a flat </span>side<span>. A vertex is .... Describe the faces edges and vertices of </span>each<span> three dimensional ... Vera's closet is </span>in the shape of<span> a </span>rectangular prism<span>. ... You </span>can<span> draw different views of three-dimensional figures. .... How </span>many square<span> millimeters of</span>wrapping paper<span>.</span>he amount of wrapping paper needed<span> to </span>cover<span> the figure represents its surface area. To find the surface area, you calculate the area of </span>each<span> face or </span>side<span> ... where SA = surface area, </span>l<span> = length, </span>w<span> = width, and </span>h<span> = height. ... the surface area of this </span>prism<span> is 158 </span>square inches<span>.  

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6 0
3 years ago
Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
What is 2/10 as a percent
Wittaler [7]
2/10 as a percent would be 20%.
5 0
3 years ago
Read 2 more answers
Which of the following is the correct graph of the solution to the inequality −18 &gt; −5x + 2 ≥ −48?
monitta

Answer:

Option D. A number line with an open circle on 4 with shading to the right and a closed circle on 10 with shading to the left

Step-by-step explanation:

we have

-18 > -5x+2 \geq -48

Divide the compound inequality into two inequalities

-5x+2 \geq -48 -----> inequality A

-5x \geq -48-2

-5x \geq -50

Multiply by -1 both sides

5x \leq 50

Divide by 5 both sides

x \leq 10

The solution of inequality A is the interval ----> (-∞,10]

All real numbers less than or equal to 10

-18 > -5x+2 -----> inequality B

-18-2 > -5x

-20 > -5x

Multiply by -1 both sides

20 < 5x

Divide by 5 both sides

4 < x

Rewrite

x > 4

The solution of the inequality B is the interval ----> (4,∞)

All real numbers greater than 4

The solution of the compound inequality is

(-∞,10] ∩ (4,∞)= (4,10]

All real numbers greater than 4 and less than or equal to 10

A number line with an open circle on 4 with shading to the right and a closed circle on 10 with shading to the left

8 0
3 years ago
Read 2 more answers
The mean amount of money spent on lunch per week for a sample of 100 students is $21. If the margin of error for the population
Digiron [165]

From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:

[$19.5, $22.5].

<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>

The confidence interval is given by the sample mean plus/minus the margin of error, hence:

  • The lower bound is the sample mean subtracted by the margin of error.
  • The upper bound is the sample mean added to the margin of error.

For this problem, we have that:

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  • The margin of error is of $1.50.

Hence the bounds are given as follows:

  • Lower bound: 21 - 1.50 = $19.50.
  • Upper bound: 21 + 1.50 = $22.50.

Hence the interval is [$19.50, $22.50].

More can be learned about confidence intervals at brainly.com/question/25890103

#SPJ1

7 0
1 year ago
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