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ivanzaharov [21]
3 years ago
8

I need help on this ​

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

The answer for this problem is 6300

Alla [95]3 years ago
5 0

Answer:

3,024,000 over 480 = 6300

Hope this helps

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Can someone help me with this question please.
valkas [14]

Answer:

56   ,    13    ,    13   ,     13

Step-by-step explanation:

That multiple of 19 is

=> 19 * 3 = 57

Now, the quantity left

=> 96-57 = 39

This can be divided equally into 3 number.

=> 39/3 = 13

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How to do this question plz answer me step by step plzz plz ​
faust18 [17]

\text{Find the perimeter of the track field}\\\\\text{We already have one of our outside value, 50. We can multiply}\\\text{this by 2}\\\\50\cdot2=100\\\\\text{Now we need to find the perimeter, better known as the circumference}\\\text{of the half circle}\\\\\text{Since there is two half circles, we can make one}\\\text{whole circle}\\\text{Use the equation:}\\\\C=\pi \cdot d\\\\\text{Plug in and solve:}\\\\C=\pi \cdot 30\\\\C=94.24778\\\\

\text{Add 100 and 94.24778}\\\\100+94.24778= 194.24778\\\\\text{Round to the nearest hundredths place:}\\\\\boxed{\text{194.25 m}}

6 0
3 years ago
For the following exercises, find the average rate of change of the functions from x = 1 to x =2.
VMariaS [17]

Answer:

For the function $f(x)=4 x-3$ the average rate change from x is equal 1 to x is equal 2 is 4 .

Step-by-step explanation:

A function is given f(x)=4x-3.

It is required to find the average rate change of the function from x is 1 to x is 2 . simplify.

Step 1 of 2

A function f(x)=4 x-3 is given.

Determine the function $f\left(x_{1}\right)$ by putting the value of x=1 in the given function.

$$\begin{aligned}&f(1)=4(1)-3 \\&f(1)=1\end{aligned}$$$$f(1)=1$$

Determine the function $f\left(x_{1}\right)$ by putting the value of x is 2 in the given function.

$$\begin{aligned}&f(2)=4(2)-3 \\&f(2)=5\end{aligned}$$

Step 2 of 2

According to the formula of average rate change of the equation $\frac{\Delta y}{\Delta x}=\frac{f\left(x_{2}\right)-f\left(x_{2}\right)}{x_{2}-x_{1}}$

Substitute the value of $f\left(x_{1}\right)$ with, $f\left(x_{1}\right)$ with $3, x_{2}$ with 2 and $x_{1}$ with 1 .

$$\begin{aligned}&\frac{\Delta y}{\Delta x}=\frac{5-1}{1} \\&\frac{\Delta y}{\Delta x}=4\end{aligned}$$

3 0
2 years ago
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