All categories

3 years ago

Draw a model for 12 divide by 6

2 answers:

6 0

You can draw 12 apples. Then for every 6 apples, draw a circle around it. The answer is the number of circles you draw which in this case is 2.

lukranit [14]3 years ago

6 0

I think you draw a circle with 12 sections and then shade 6

You might be interested in

Convert.<br> 300 liters<br> to hectoliters

kumpel [21]

Answer:

wouldnt it be 3?

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the equation of a quadratic function p with rational coefficients that has a zero of 3-i

Kryger [21]

Answer:

p = x² − 6x + 10

Step-by-step explanation:

Complex roots come in conjugate pairs. So if 3−i is a root, then 3+i is also a root.

p = (x − (3−i)) (x − (3+i))

p = x² − (3+i)x − (3−i)x + (3−i)(3+i)

p = x² − 3x − ix − 3x + ix + (9 − i²)

p = x² − 6x + 10

You can check your answer using the quadratic formula.

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ 6 ± √(36 − 40) ] / 2

x = (6 ± 2i) / 2

x = 3 ± i

6 0

3 years ago

The plesiosaur’s stomach had 2.25 kilograms of gastroliths. The largest stone was 0.074 meter long, 0.048 meter wide, and 0.022

Annette [7]

Answer:

2.25=5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

alexdok [17]

Anything to the 0th power is always equal to one.

3 0

4 years ago

Read 2 more answers

The numbers 1, 2, 3, 4,5, 6, 7, 8, 9 are arranged in a list so that each number is either greater than all the numbers that come

Nina [5.8K]

The lists of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 that are possible is; 256

<h3>How to Solve Probability Combinations?</h3>

We are told that the last digit has to be either a one (1) or nine (9), then are two (2) options (>,<) for the remaining eight digits, so there are 2⁸ = 256 arraignments where each digit is either greater than or less than the preceding digits. This can be confirmed as below;

Numbers beginning with 1 = 8C0 = 1

Numbers beginning with 2 = 8C1 = 8

Numbers beginning with 3 = 8C2 = 28

Numbers beginning with 4 = 8C3 = 56

Numbers beginning with 5 = 8C4 = 70

Numbers beginning with 6 = 8C5 = 56

Numbers beginning with 7 = 8C6 = 28

Numbers beginning with 8 = 8C7 = 8

Numbers beginning with 9 = 8C8 = 1

Total lists of numbers possible = 1 + 8 + 28 + 56 + 70 + 56 + 28 + 8 + 1 = 256

Read more about Probability Combinations at; brainly.com/question/25688842

#SPJ1

4 0

2 years ago