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Vikentia [17]
3 years ago
12

I have an unknown initial volume of gas

Chemistry
1 answer:
earnstyle [38]3 years ago
5 0

Answer:

V₁ = 0.025 Liters = 25 ml

Explanation:

P₁ = 6 Atm      P₂ = 7800mm/760mm/Atm = 0.01 Atm

V₁ = ?              V₂ = 29 Liters

T₁ = 115 K        T₂ = 225 K

P₁V₁/T₁ = P₂V₂/T₂ => V₁ = P₂V₂T₁/P₁T₂

V₁ = (0.01 Atm)(29L)(115K)/(6 Atm)(225K) = 0.025 Liters = 25ml

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Atoms and the chemical bonds that connect them cannot be observed with your eyes, so it is necessary to use a
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Give an example of a solution that can be seperated by simple distilation.​
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3 years ago
La densidad del óxido de magnesio. MgO, es de 3.581 g/cm3 El MgO, es de 3.581 g/cm3 El MgO cristaliza con ordenamiento cúbico co
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Answer:

a=4.213cm

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Explanation:

Hola.

En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:

\rho =\frac{#at*M}{a^3N_A}

En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:

3.581g/mol = \frac{4atom/celda*40.3g/mol}{a^3*6.02x10^{23}atom/mol}

Despejando para a, obtenemos:

a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm

Finalmente, el radio lo calculamos como:

r=\frac{\sqrt{2}*a}{4}=\frac{\sqrt{2}*4.213x10^{-8}cm}{4}\\\\r=1.490x10^{-8}cm

¡Saludos!

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3 years ago
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4 years ago
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