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juin [17]
3 years ago
7

What force is required to accelerate an object javinh a mass of 3 kg at 5 m/s

Physics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Force (in newtons) = mass (in kg) x acceleration (m/sec)  

Therefore Force = 3kg x 5m/s ==> 15 newtons  

----------------------------------  

75 newtons = m x 10 ==> 7.5kg  


I believe...?

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Calculate the kinetic energy of a 0.032 kg ball as it leaves a hand to be thrown upwards at 6.2 m/s
AnnZ [28]

Answer:

The ball will have a kinetic energy of 0.615 Joules.

Explanation:

Use the kinetic energy formula

E_k = \frac{1}{2}mv^2 = \frac{1}{2}0.032kg\cdot 6.2^2 \frac{m^2}{s^2}= 0.615J

The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)

3 0
4 years ago
A certain brand of hot dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowi
Whitepunk [10]

Answer: 43s

Explanation:

The stored energy across a plate can be measured by calculating the electric charge and the potential difference. Also, the quantity of electricity can be measured by multiplying the current in the circuit with the time taken.

Given

Potential difference, V = 120 v

Current, I = 11.5 A

Energy, E = 59 kJ

Remember,

E = QV, so that

Q = E/V

Q = 59000/120

Q = 491.67 C

Q = IT

491.67 = 11.5*t

t = 491.67/11.5

t = 42.75s ~ 43s

Time taken to cook the 3 hot dogs simultaneously is 43s

5 0
3 years ago
What is the volume of an object with a mass of 15 grams and a density<br> of 2 g/ml
OleMash [197]

Answer: 7.5 ml

Explanation: Density= mass/ volume.

So, volume = mass / density

                    = 15g / 2 g/ml

                    = 7.5 ml

7 0
3 years ago
Suppose a vector v makes an angle theta with respect to the y axis, what could be the x and y components of the vector v
gtnhenbr [62]

If the angle between the vector and the y-axis is  Θ ,
then the y-component of the vector is

                   (length of the vector) times  cosine( Θ ),

and the x-component of the vector is

                   (length of the vector) times  sine( Θ ) .

8 0
3 years ago
A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the
Nesterboy [21]

Answer:

A.) 1372 N

B.) 1316 N

C.) 1428 N

Explanation:

Given that a 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following cases:

a. The load moves downward at a constant velocity

At constant velocity, acceleration = 0

T - mg = ma

T - mg = 0

T = mg

T = 140 × 9.8

T = 1372N

b. The load accelerates downward at a rate 0.4 m/s??

Mg - T = ma

140 × 9.8 - T = 140 × 0.4

1372 - T = 56

-T = 56 - 1372

- T = - 1316

T = 1316N

C. The load accelerates upward at a rate 0.4 m/s??

T - mg = ma

T - 140 × 9.8 = 140 × 0.4

T - 1372 = 56

T = 56 + 1372

T = 1428N

8 0
3 years ago
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