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juin [17]
3 years ago
7

What force is required to accelerate an object javinh a mass of 3 kg at 5 m/s

Physics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Force (in newtons) = mass (in kg) x acceleration (m/sec)  

Therefore Force = 3kg x 5m/s ==> 15 newtons  

----------------------------------  

75 newtons = m x 10 ==> 7.5kg  


I believe...?

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Which of the Jovian planets have rings?
fenix001 [56]
All of the four have rings, but if i'm not mistaken Saturn is the only visible ring.

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6 0
3 years ago
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A deer is running from a mountain lion when it encounters a fence that is 1.50 m high. Seeing the fence, the deer jumps, leaving
Novosadov [1.4K]

Answer:

Explanation:

Given

Initial Velocity (u)=13 m/s

angle=29^{\circ}

distance between fence and deer=2.5 m

We consider deer jump similar to projectile motion

equation of trajectory

y=xtan\theta -\frac{gx^2}{2u^2(cos\theta )^2}

y=2.5tan(29)-\frac{9.8\times 2.5^2}{2\times 13^2\times (cos29)^2}

y=1.385-0.2368=1.148 m

Thus deer will cross the fence with an difference in its jump and fence

1.5-1.148=0.351 m

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{13^2\times (sin29)^2}{2\times 9.8}

h_{max}=2.02 m

so deer rises during when it is over fence

8 0
4 years ago
Imagine you are sitting on a sled and someone is about to push you down a hill. Which statement is accurate?
Dima020 [189]

The answer is:

Forces acting on the sled are paired with equal and opposite forces.

The explanation:

About to push you, this means that he doesn't push yet. If the sled is on level ground and no one is pushing it, then forces are equal and opposite.

The gravity force pulls down and the ground pushes up.

This is Newton's third law:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

We can also see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool.

6 0
3 years ago
Read 2 more answers
An object with mass m = 0.56 kg is attached to a string of length r = 0.72 m and is rotating with an angular velocity ω = 1.155
Marta_Voda [28]

Answer:

The centripetal force is 0.54 N.

Explanation:

mass, m = 0.56 kg

radius, r = 0.72 m

angular speed, w = 1.155 rad/s

The centripetal force is given by

F = m r w^2\\\\F =0.56\times 0.72\times 1.155\times 1.155\\\\F = 0.54 N

6 0
3 years ago
A 25 kg lamp is hanging from a rope. What is the tension force being supplied by the rope?
d1i1m1o1n [39]

The tension force being supplied by the rope is 245 N.

<h3>What is tension force?</h3>
  • Tension force is the force exerted on a rope or cord due to the weight of an object suspended from it.

The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;

T = mg

where;

  • m is the mass = 25 kg
  • g is acceleration due to gravity = 9.8 m/s²

T = 25 x 9.8

T = 245 N

Thus, the tension force being supplied by the rope is 245 N.

Learn more about tension force here: brainly.com/question/2008782

4 0
2 years ago
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